A bag contains 7 red marbles, 3 blue marbles and 5 green marbles. If three marbles

Mathematics

1 answer:

worty [1.4K]3 years ago

8 0

Answer:

3.7%

Step-by-step explanation:

We know that from this situation, the probability of drawing a single green marble is 1/3. However, to find the probability of drawing 3 green marbles, we will need to do:

$P= \frac{1}{3}* \frac{1}{3}*\frac{1}{3}$

We get a probability of:

$P= \frac{1}{27}$

This converts to a percentage of:

$\frac{1}{27}= 0.037 \\ 0.037*100= 3.7%$

We get a percentage of 3.7%

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erastovalidia [21]

Answer:

First box:

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Second Box:

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Third Box:

5 x 8

Step-by-step explanation:

8 0

3 years ago

19. Solve the equation 3cos x = 8tan x, between Oº and 360°

Alex

$3\cos x=5\tan x\\\\3\cos x=5\cdot\dfrac{\sin x}{\cos x}\\\\3\cos^2 x=5\sin x\\\\3(1-\sin^2x)=5\sin x\\\\-3\sin^2x-5\sin x+3=0\\\\t=\sin x\qquad\qqaud t\in\\\\-3t^2-5t+3=0\\\\3t^2+5t-3=0\quad\implies\quad a=3\,,\ b=5\,,\ c=-3\\\\t=\dfrac{-5\pm\sqrt{5^2-4\cdot3\cdot(-3)}}{2\cdot3}=\dfrac{-5\pm\sqrt{25+36}}{6}=\dfrac{-5\pm\sqrt{61}}{6}\\\\t_1=\dfrac{-5+\sqrt{61}}{6}\approx0.4684\ ,\qquad t_2=\dfrac{-5-\sqrt{61}}{6}\approx-2.136\notin$

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