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2 years ago

Which has no real roots?

Mathematics

1 answer:

Alexxandr [17]2 years ago

4 0

bruh where the problom tho

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Please help! I really need this

olga55 [171]

9514 1404 393

Answer:

see below

Step-by-step explanation:

You might do well to refer to the proof referenced here--the previous slide. We assume it more or less matches what we've done in the attachment.

6 0

2 years ago

Which expression is equivalent to 2(3 - x) - 12 + 4x? 2x - 6 3х - 6 3x-7 2x - 7

Simora [160]

Answer:

2x - 6

Step-by-step explanation:

2(3 - x) - 12 + 4x =

6 - 2x - 12 + 4x =

-6 + 2x =

2x - 6

8 0

2 years ago

What is an equation of the line passing between(4, -6) and (12, -8)?*

I am Lyosha [343]

Answer:

y= -1/4x - 5

Step-by-step explanation:

first you need to find the slope.

to do this you can use the equation: change in y/change in x which is also y2 - y1/x2-x1

-8 - (-6)/12-4

-2/8

-1/4 = slope

since the line's equation is y = mx + b, we still need to find the y-intercept. we can do this by just plugging in one of the points

-6 = -1/4(4) + b

-6 = -1 + b

-5 = b

so the final equation is y= -1/4x - 5

4 0

2 years ago

How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$

8 0

2 years ago

Find the value of x in each triangle

mrs_skeptik [129]

Answer:

90°

Step-by-step explanation:

x + 37 + 53 = 180 (ANGLE SUM PROPERTY)

x + 90 = 180

x = 180-90

x = 90°

7 0

2 years ago