All categories

3 years ago

Is there a real number whose square is −1? a. Is there a real number x such that ? b. Does there exist such that x2 = −1?

Mathematics

1 answer:

Sauron [17]3 years ago

5 0

Answer:

a. $x^2=-1$

b.a real number x

Step-by-step explanation:

We are given that statement.

We have to rewrite the given statement using variable or variables.

Statement:Is there a real number whose square is -1.

a.Let x bet the real number

The square of real number x written as $x^2$

According to question

$x^2=-1$

Therefore,

Is there a real number x such that $x^2=-1$

b.Does there exist a real number x such that

$x^2=-1$

You might be interested in

What is the following product? Assume x>/=0 ^3sqrt(x^2)*^sqrtx^3

RoseWind [281]

Answer:

$x(\sqrt[12]{x^5} )$

Step-by-step explanation:

We need to remember 2 rules when doing these:

1. $\sqrt[n]{x^a} =x^{\frac{a}{n}}$

2. $x^a*x^b=x^{ab}$

Using these 2 rules, we can simplify the product (steps shown below):

$\sqrt[3]{x^2} *\sqrt[4]{x^3} \\=x^{\frac{2}{3}}*x^{\frac{3}{4}}\\=x^{\frac{2}{3}+\frac{3}{4}}\\=x^{\frac{17}{12}}\\=x^{\frac{12}{12}+\frac{5}{12}}\\=x(x^{\frac{5}{12}})\\=x(\sqrt[12]{x^5} )$

Rearranging, we see that it is the third choice.

7 0

2 years ago

−1.64 as a mixed number in simplest form.

liraira [26]

Convert to a mixed number by placing the numbers to the right of the decimal over 100. Reduce the fraction. Then, convert the mixed number to an improper fraction by multiplying the denominator by the whole number and adding the numerator to get the new numerator. Place this new numerator over the original denominator.

-41\25

4 0

2 years ago

Let f(x) = 3x^2 – 8x + 5 and let g(x) = 2x – 8. Find

fenix001 [56]

Answer:

B. 3x² – 10x + 13

Step-by-step explanation:

given:

f(x) = 3x² – 8x + 5

g(x) = 2x – 8

f(x) - g(x)

= (3x² – 8x + 5) - (2x – 8)