Answer:
C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.
Step-by-step explanation:
Let μ be the the average attendance at games of the football team
The claim: the average attendance at games is over 523
Null and alternative hypotheses are:
: μ=523
: μ>523
The conclusion is failure to reject the null hypothesis.
This means that <em>test statistic</em> is lower than <em>critical value</em>. Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.
That is no significant evidence that the average attendance at games of the football team is greater than 523.
Answer:
y = -0.8x - 5
Step-by-step explanation:
x1 = (XA + XB) / 2 = -5
y1 = (YA + YB) / 2 = -1
m = (XA - XB) / (YA - YB) = -0
__________________________________________
(y - -1) = -0.8(x - -5)
y - -1 = -0.8x - 4
y = -0.8x - 4 + -1
y = -0.8x - 5
Answer:
9/10
Step-by-step explanation:
2 2/5 - 1 1/2
Get a common denominator of 10
2 2/5 *2/2 = 2 4/10
1 1/2 *5/5 = 1 5/10
2 4/10 - 1 5/10
Borrow from the 2 as 10/10
1 + 10/10 +4/10 - 1 5/10
1 14/10 - 1 5/10
9/10
7 because the 3 is the coefficient and the x is the variable. The + is the operator so that leaves you the 7
<h2>
Answer:</h2>
# short sleeved shirts sold is 50
# long sleeved shirts sold 35
<h2>
Step-by-step explanation:</h2>
First, you need to set up the equation.
(5x)+10*(85-x)=600
5x+850-10x=600
-5x+850=600
-5x=600-850
-5x=-250
x=50
After you solve the equation, you know, that 50 short sleeve t-shirts were sold. Now, you need to find out how many long sleeved t-shirts were sold. 85-50=35. Now you know, that there were 35 long sleeved t-shirt sold.
You can now check your answers. 50*5 + 35*10=600
That is correct.
I hoped I helped you. I will be really glad, if you mark my answer with brainliest.
