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avanturin [10]
3 years ago
8

Please help me with this :)

Mathematics
1 answer:
Elena L [17]3 years ago
8 0

Answer:

i think :

3 hours and 35 min

2 hours and 45 min

4 hours and 30 min

4 hours and 5 min

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Solve that for me :)
gavmur [86]

Answer:

2/5

Step-by-step explanation:

Out of the available options on the spinner, only 1 and 5 are factors of 25.

=> Outcomes = 2

=> Total outcomes = 5

P (factor of 25) = 2/5

Hope it helps.

5 0
2 years ago
Read 2 more answers
C6H12O2 + O2 --> 6H2O + 6CO2 + 2800 kJ
DIA [1.3K]

Answer:

This is the equation for cellular respiration.

Step-by-step explanation:

C6H1206 is glucose. O2 is oxygen. They react to produce 6H20, which is water, and 6CO2, which is carbon dioxide. Energy is also produced which is represented by 2800 kJ. Energy is created in the form of ATP and heat.

3 0
3 years ago
What is the scale factor of this dilation?
Luden [163]
The answer is 3/5 because i did the math on my paper and yea
8 0
3 years ago
An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with
AleksandrR [38]

Answer:

U₂₁ and U₂₂ fits in the line of upper triangular

Step-by-step explanation:

As explain in the question

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with all zeros above its diagonal.

(as shown in the attached image)

(a)for all 3×3 upper triangular matirices U, verify that U2 is also upper triangular

for a matrices U (having a 3*3 matrix), assuming for example, U is given below:

U = \left[\begin{array}{ccc}1&2&3\\0&5&6\\0&0&9\end{array}\right]

the element in the upper triangular are 1,2,3,5,6,9 (U₁₁, U₁₂, U₁₃; , U₂₂, U₂₃, U₂₂)

while lower triangular are 0,0,0, the element in the lower triangular are (U₂₁, U₃₁,U₃₂)

U₂₁ and U₂₂ fits in the line of upper triangular

8 0
3 years ago
Can someone please help me with this!!
Aloiza [94]

Answer:

407 yd^{2}

Step-by-step explanation:

first find the area of the rectangle, which would be 16*13 = 208yd²

then find the arc length of the sector, which is about 30.6yd

use the arc length to find the area of the sector, which is about 199.09yd²

add together the area of the rectangle and sector:

199.09 + 208 ≈ 407

8 0
3 years ago
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