Answer/Step-by-step explanation:
Recall the acronym SOHCAHTOA. This is what we would apply as appropriate in each case.
8. θ = 40°
Opp = m
Adj = 20
Thus, apply TOA
Tan (θ) = opp/adj
Plug in the values
Tan (40) = m/20 (equation)
20×Tan(40) = m
m = 16.7820
9. θ = 22°
Hyp = w
Adj = 18
Thus, apply CAH
Cos (θ) = adj/hyp
Plug in the values
Cos 22 = 18/w (equation)
w×cos 22 = 18
w = 18/(cos 22)
w = 19.4136
10. θ = 35°
Hyp = 55
Opp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 35 = x/55 (equation)
55×sin 35 = x
x = 31.5467
11. θ = 33°
Hyp = 19
Adj = x
Thus, apply CAH
Cos θ = adj/hyp
Plug in the values
Cos 33 = x/19 (equation)
19×cos 33 = x
x = 15.9347
12. θ = 17°
Opp = 7
Hyp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 17 = 7/x (equation)
x×sin 17 = 7
x = 7/(sin 17)
x = 23.9421
13. θ = 40°
Opp = 15
Adj = x
Thus, apply TOA
Tan θ = opp/adj
Plug in the values
Tan 40 = 15/x (equation)
x×Tan 40 = 15
x = 15/(Tan 40)
x = 17.8763
It is given that batteries come in a packs of 4. It means in each pack there are 4 batteries.
Joe used 58 batteries . So to find the total number of packets of batteries joe has to open is
Number of batteries used / Total number of batteries in each packet
= 58 / 4
= 14.5
The number of battery can not be in decimal. So we will round the answer to integer. If we round it to 14 it means 14 packets. But in 14 packets there are 14*4 = 56 batteries .
But we know that Joe used 58 batteries. So we will round the final answer to 15.
It means Joe has to open 15 packets of batteries.
46. Fortysix times 2 equals 92.
Answer:
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p-by-step explanation:
