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Gnom [1K]
3 years ago
15

Let f(x) = 3x - 7 and g(x) = -2x -6. Find (f x g)(4) Include steps please.

Mathematics
1 answer:
siniylev [52]3 years ago
7 0
Here's the derivation.
(f x g)(4) = f(4) x g(4)

So applying the derived equation.
(f x g)(4) = 3(4) - 7 * -2(4) - 6
(f x g)(4) = 5 * -2
(f x g)(4) = -10
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Given: 2q – r = 4p, 2r = q, r = 2p; Prove: q = r
Gnoma [55]

Answer:

q = r

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given    2q – r = 4p ...(i)

                  2r = q...(ii)

                  r = 2p ...(iii)

Substitute 2r = q in equation (i)

            <em>   2(2r) – r = 4p </em>

                     3 r = 4 p

                 <em>  2 r + r = 4 p</em>

                   2 r + 2 p = 4 p

                  2 r = 2 p

                 <em>  q = r</em>

         

5 0
3 years ago
Which point on the graph of g(x)=(1/5)^x? HELPP
Cloud [144]

Answer:

(-1,5) and (3, \frac{1}{125}) are points on the graph

Step-by-step explanation:

Given

g(x) = \frac{1}{5}^x

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-1}

Convert to index form

g(x) = 1/(\frac{1}{5})

Change / to *

g(x) = 1*(\frac{5}{1})

g(x) = 5

This satisfies (-1,5)

<em>Hence, (-1,5) is on the graph</em>

<em></em>

B. (1,0)

x = 1

Substitute 1 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^1

g(x) = \frac{1}{5}

<em>(1,0) is not on the graph because g(x) is not equal to 0</em>

C. (3, \frac{1}{125})

x = 3

Substitute 3 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^3

Apply law of indices

g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}

g(x) = \frac{1}{125}

This satisfies (3, \frac{1}{125})

<em>Hence, </em>(3, \frac{1}{125})<em> is on the graph</em>

<em></em>

D.  (-2, \frac{1}{25})

x = -2

Substitute -2 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-2}

Convert to index form

g(x) = 1/(\frac{1}{5}^2)

g(x) = 1/(\frac{1}{5}*\frac{1}{5})

g(x) = 1/(\frac{1}{25})

Change / to *

g(x) = 1*(\frac{25}{1})

g(x) = 25

This does not satisfy  (-2, \frac{1}{25})

<em>Hence, </em> (-2, \frac{1}{25})<em> is not on the graph</em>

8 0
4 years ago
An ad agency is developing a campaign to promote a business opening in a new mall development. To develop an appropriate mailing
Ipatiy [6.2K]

Answer:

The answer is 1/3 or 0.33

Step-by-step explanation:

Let's consider the following ocurrences:

A: A person has a MasterCard

B: A person has an American Express

The data says:

P(A∩B) = 0.2

P(A without B) = 0.4

P(B without A) = 0.1

Then, P(A) =  P(A∩B) +P(A without B) = 0.2+0.4 = 0.6

By conditional probability theory:

P (B/A) = P(A∩B) / P(A) = 0.2 / 0.6 = 1/3 = 0.33

Thus

P(B/A) = 1/3 = 0.33

6 0
4 years ago
Write the set { 1, 3, 7, 15, 31, 63 } in set builder form ​
Sholpan [36]

Answer:

{ x : x = 2^n -1 , n ∈ N}

Where N is the set of natural numbers

Step-by-step explanation:

Mathematically, we can rewrite each term in the set as follows;

1 = 2^1 - 1

3 = 2^2 -1

7 = 2^3 -1

15 = 2^4-1

31 = 2^5-1

63 = 2^6 -1

so we can conclude that the nth term is 2^n -1

So writing this in set builder notation, we have;

{ x : x = 2^n -1 , n ∈ N}

Where N is the set of natural numbers

3 0
3 years ago
7 is what percentage of 14?
rusak2 [61]

7 is 50% of 14..........

4 0
3 years ago
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