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3 years ago

What is the base of a parallelogram whose height is 4cm and whose area is 44cm2

Mathematics

2 answers:

Alex17521 [72]3 years ago

7 0

The base is 11 centimeters

hoa [83]3 years ago

3 0

11cm is the base of parallelogram

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In a right angled triangke abc the perpendicular and the base measure 3 cm find hypotenus and three trignometrice ratios

Ierofanga [76]

Given:

In a right angled triangle ABC the perpendicular and the base measure 3 cm.

To find:

The hypotenuse and three trigonometric ratios.

Solution:

Pythagoras theorem:

$Hypotenuse^2=Perpendicular^2+Base^2$

Use Pythagoras theorem in triangle ABC.

$Hypotenuse^2=(3)^2+(3)^2$

$Hypotenuse^2=9+9$

$Hypotenuse=\sqrt{18}$

$Hypotenuse=3\sqrt{2}$

The three trigonometric ratios are

$\sin \theta=\dfrac{Perpendicular}{Hypotenuse}$

$\sin \theta=\dfrac{3}{3\sqrt{2}}$

$\sin \theta=\dfrac{1}{\sqrt{2}}$

Similarly,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos \theta=\dfrac{3}{3\sqrt{2}}$

$\cos \theta=\dfrac{1}{\sqrt{2}}$

And,

$\tan \theta=\dfrac{Perpendicular}{Base}$

$\tan \theta=\dfrac{3}{3}$

$\tan \theta=1$

Therefore, the hypotenuse is $3\sqrt{2}$ cm and three trigonometric ratios are $\sin \theta=\dfrac{1}{\sqrt{2}}, \cos \theta=\dfrac{1}{\sqrt{2}}, \tan \theta=1$ .

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2 years ago

The students in Ms. Garris's class collected items to put in gift baskets for the Senior Center. They collected 12 magazines, 24

marta [7]

Answer:

24 :)

Step-by-step explanation:

12 divided by 3 = 4

24 divided by 3 = 8

36 divided by 3 = 12

4 + 8 = 12

12 + 12 = 24

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Answer:

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SOLUTION

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