The percentage of the scores that are between 75.8 and 89 is; 95%
<h3>How to find the percentage from z-score?</h3>
We are given;
Population mean; μ
Standard deviation; σ = 3.3
Thus;
z-score for a mean score of 75.8 is;
z = (75.8 - 82.4)/3.3
z = -2
z-score for a mean score of 89 is;
z = (89 - 82.4)/3.3
z = 2
From online p-value from z-score calculator, the p-value between both z-scores is;
p-value = 0.9545 = 95.45%
Approximating to the nearest percent = 95%
Read more about z-score at; brainly.com/question/25638875
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