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Inga [223]
3 years ago
15

QUICK PLEASE!

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0

Answer:

1, 3, 4, 5 and 6

Step-by-step explanation:

A negative and a negative equals a positive, hope that helps in future math problems

Over [174]3 years ago
4 0
1,3,4,5, and 6......
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Really easy! PLEASE HELP, I Will mark Brainliest
zlopas [31]

Answer:

(x,y)=(-5,5)

Step-by-step explanation:

7 0
3 years ago
Somebody pls help me!!!
Setler [38]
<h3>Answer:  60 units</h3>

=====================================================

Explanation:

The similar red marks on the angles tell us those angles are congruent. So they are the same measure.

The sides opposite those congruent angles are the same length. This means AC = BC. This triangle is isosceles.

--------------

Solve for x

AC = BC

5x-8 = 2x+7 .... substitution

5x-8-2x = 7 ... subtract 2x from both sides

5x-2x = 7+8 ..... add 8 to both sides

3x = 15

x = 15/3 ... divide both sides by 3

x = 5

---------------

Use that x value to compute each side length

AB = 3x+11 = 3*5+11 = 15+11 = 26

BC = 2x+7 = 2*5+7 = 10+7 = 17

CA = 5x-8 = 5*5-8 = 25-8 = 17

Note how BC and CA are the same length (17 units). This helps confirm we have the right x value.

----------------

The last step is to add up all the side lengths to get the perimeter

perimeter of triangle = sum of all the sides

perimeter of triangle = side1 + side2 + side3

perimeter of triangle ABC = AB + BC + CA

perimeter of triangle ABC = 26 + 17 + 17

perimeter of triangle ABC = 60 units

4 0
3 years ago
Read 2 more answers
Help me and I’ll give you brainliest
mash [69]

Answer:

124

Step-by-step explanation:

5 0
3 years ago
May someone help me out with this question please please
Anuta_ua [19.1K]

4/52

then u would divide both numbers by 4 and get

1/13 

3 0
3 years ago
Which of the segments below is a secant?<br><br> A. XB<br> B. OB<br> C. XV<br> D. XY
s2008m [1.1K]
A secant of a curve is a line that intersects the curve at a minimum of two distinct points.

So the answer is D. XY
5 0
3 years ago
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