Okay so this is easy conversion.
40 quarters=10$
60 dimes =24 quarters
30 dimes= 12 quarters=3$
200 dimes=80 quarters
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Answer:</h3>

<h3>
Step-by-step explanation:</h3>
In this question, we're trying to find the probability of it being cloudy and raining.
In this case, we know that:
- Probability of it being cloudy is 30%
- Probability of it raining is 25% (this is necessarily not needed)
- If it's cloud, the probability of it raining is 45%
With the information above, we can find the probability.
We know that from a 100% scale, the chance of it being cloudy is 30%.
We know that if it's cloudy, the chances of raining is 45%
To find the probability of it being cloudy and raining, we would multiply 0.3 (30%) by 0.45 (45%)
Solve:

Your answer would be C). 13.5%
<h3>
I hope this helped you out.</h3><h3>
Good luck on your academics.</h3><h3>
Have a fantastic day!</h3>
Answer: Hello mate!
A direct variation implies that, if y is the dependent variable that varies with the variable x; then: y = k*x where k is a real number.
An inverse variation has the form y = k/x where also k is a real number.
them, if we define s as the hours that Bob spends studying, and b as the hours that he spends playing baseball, then the equation that represents the score is:
Score(s,b) = k*s/b
we know that if s = 6, and b = 7, then the score is 72; with this information, we could obtain the value of the constant k.
score(6,7) = 72 =k*6/7 = k*
then k = 72*(7/6) = 61.7
now if s = 4 and b = 6, the score that he should expect is:
score( 4, 6) = 61.7*(4/6) = 41
Answer: The probability would 0.35770234986 or 35%
Step-by-step explanation:
There are 187 nickels and 66 dimes in the jar.
Step-by-step explanation:
Given,
Total coins = 253
Value of coins = $15.95 = 15.95*100 = 1595 cents
Value of each nickel = 5 cents
Value of each dime = 10 cents
According to given statement;
x+y=253 Eqn 1
5x+10y=1595 Eqn 2
Multiplying Eqn 1 by 5

Subtracting Eqn 3 from Eqn 2

Dividing both sides by 5

Putting y=66 in Eqn 1

There are 187 nickels and 66 dimes in the jar.
Keywords: linear equation, elimination method
Learn more about elimination method at:
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