Answer:
C) Both functions are decreasing and both are positive on the interval (0;2)
Step-by-step explanation:
As known the exponent function has no minimum and has no maximum.
Otherwise exponent function can be only or increasing or decreasing for all x.
That means that in case y(x2)>y(x1) and if x2>x1- function is increasing.
That means that in case y(x2)<y(x1) and if x2>x1- function is decreasing.
Lets check what is going on with the function f(x)
If x1=0 f(x1)=24
If x2=2 f(x2)=0
So x2>x1 however f(x2)<f(x1)=> function is decreasing
Similarly g(x)
If x1=0 g(x1)=15
If x2=2 g(x2)=0
So x2>x1 however g(x2)<g(x1) => function is decreasing
So bothfunctions are decreasing.
Because f(x) is decreasing the function meaning with argument x1=0 has max in the interval x∈(0;2) And function meaning has the minimum if argument x2=2. So the function F(x) in interval (0;2) is changing from 24 to 0 => is positive on the interval (0,2)
The same is with g(x) . g(x) gonna be positive on the interval (0;2)
If it helps at all there is this graphing webpage called desmos.com it helps with tables and a lot of graphing stuff.
Your best bet would be to google it dog
Add all the crayons together
will give you 25
green crayons are 10
so 10/25
Answer:
Consider the following explanation
Step-by-step explanation:
The experimental unit here is a cat.
The explanatory variable is a numerical variable which identifies the time for which a given cat is subjected to hunger deprivation.
The response variable is a categorical variable which identifies whether there is an increase in aggression in a given cat.
The interacting variable is a numerical variable where weight of a given cat is noted.
Population here is the 10 cats.
There is no control group for the given experiment.
Dependent variable is the weight of each cat as it changes as the experimental units are subjected to hunger deprivation.
