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vekshin1
3 years ago
5

Find -3A+6B A=[-3 5 -6] [9 -5 3] B=[-2 6 7] [2 -1 -6]

Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

A=\left[\begin{array}{ccc}-3&5&-6\\9&-5&3\end{array}\right];\ B=\left[\begin{array}{ccc}-2&6&7\\2&-1&-6\end{array}\right]\\\\-3A=\left[\begin{array}{ccc}(-3)(3)&(5)(3)&(-6)(3)\\(9)(3)&(-5)(3)&(3)(3)\end{array}\right]=\left[\begin{array}{ccc}-9&15&-18\\27&-15&9\end{array}\right] \\\\6B=\left[\begin{array}{ccc}(-2)(6)&(6)(6)&(7)(6)\\(2)(6)&(-1)(6)&(-6)(6)\end{array}\right]=\left[\begin{array}{ccc}-12&36&42\\12&-6&-36\end{array}\right]

-3A+6B=\left[\begin{array}{ccc}-9+(-12)&15+36&-18+42\\27+12&-15+(-6)&9+(-36)\end{array}\right]\\\\-3A+6B=\left[\begin{array}{ccc}-21&51&24\\39&-21&-27\end{array}\right]

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<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>

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Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

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<u>Finding the distance of Jabril:</u>

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Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

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This can lead to two possible solutions:

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Possible solution #2:

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