All categories

4 years ago

How do I solve this (x+10)²=36

Mathematics

2 answers:

Alex4 years ago

6 0

x=−4,−16 here is your answer.

adoni [48]4 years ago

3 0

Go ahead and simplify;
$x^{2} +20x+100=36$
$x^{2} +20x+100-36=0$
$x^{2} +20x+64=0$
$x^{2} +4x+16x+64$
x(x+4)+16(x+4)=0
(x+16)(x+4)=0
x+16=0
x=-16
x+4=0
x=-4

You might be interested in

Evaluate 4x-6y when x=-3 y=-1

pogonyaev

Answer:

First we substitute

4(-3) - 6(-1)

-7 -6

-13

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A wheel in this scale drawing is 4 cm wide. The ratio of the drawing is 1:14. How wide is the actual wheel in cm?

bagirrra123 [75]

1:14 means that for every 1 cm it is drawn at it is actually 14 cm

so multiply 4 x 14 = 56

it is actually 56 cm wide

7 0

3 years ago

The table shows the number of words Marla can type in a given time.

Brrunno [24]

Answer:

wheres the graph?

Step-by-step explanation:

8 0

3 years ago

A patient drinks 5 12ounce cups of coffee daily. The doctor recommends cutting back 60%, how many ounces of coffee can the patie

maksim [4K]

The patient is recommended to take 24 ounces of coffee per day.

Step-by-step explanation:

Patient normal intake of coffee daily = 5 times 12 ounces

= 5 × 12 = 60 ounces

Doctor recommends to cut off 60 % of the normal intake of coffee.

And advised to take only 40 % of the daily intake of coffee.

So 60 % of 60 ounces can be calculated as,

$$\frac{60 \times 60}{100}$ = 36 ounces

40 % of 60 ounces is 24 ounces.

So 60 - 36 = 24 ounces of coffee per day

6 0

3 years ago

Pleasee help ASAP!! No links pleaseee!!!

Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(2-0)^2+(4-1)^2}$

$AB=\sqrt{(2)^2+(3)^2}$

$AB=\sqrt{4+9}$

$AB=\sqrt{13}$

Similarly,

$BC=\sqrt{(6-2)^2+(0-4)^2}$

$BC=\sqrt{(4)^2+(-4)^2}$

$BC=\sqrt{16+16}$

$BC=\sqrt{32}$

$BC=4\sqrt{2}$

Now, the length of the rectangle is $AB=\sqrt{13}$ and the width of the rectangle is $BC=4\sqrt{2}$ . So, the area of the rectangle is:

$A=length \times width$

$A=\sqrt{13}\times 4\sqrt{2}$

$A=4\sqrt{26}$

$A\approx 20$

Therefore, the area of the rectangle is 20 square units.

3 0

3 years ago