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3 years ago

Simplify completely. square root of 18y^10

Mathematics

1 answer:

NemiM [27]3 years ago

3 0

sqrt (18y10) =
3 y5 • sqrt(2)

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The solution to a system of linear equations is (-3,-3) Which system of linear equations has this point as its solution? x -5y=-

Ann [662]

Answer:

$x-5y=12$ and $3x+2y=-15$

Step-by-step explanation:

The first system is

$x-5y=-12$ and $3x+2y=-15$

We substitute x=-3 and y=-3

$-3-5*-3=12\ne-12$ and $3*-3+2*-3=-15$

Both equations are not satisfied

The next system is

$x-5y=12$ and $3x+2y=-15$

We substitute x=-3 and y=-3

$-3-5*-3=12$ and $3*-3+2*-3=-15\ne15$

Both equations are satisfied

The next system is

$x-5y=-12$ and $3x+2y=15$

We substitute x=-3 and y=-3

$-3-5*-3=12\ne12$ and $3*-3+2*-3=-15$

Both equations are not satisfied

The next system is

$x-5y=12$ and $3x+2y=15$

We substitute x=-3 and y=-3

$-3-5*-3=12\ne-12$ and $3*-3+2*-3=-15$

Both equations are not satisfied

6 0

4 years ago

Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy. x5y2 − x4y

il63 [147K]

Answer:

dx/dy = (x^4 - 2x^5y - 6xy^2) / (5x^4y^2 - 4x^3y + 2y^3).

Step-by-step explanation:

x^5y^2 − x^4y + 2xy^3 = 0

Applying the Product and Chain Rules:

y^2*5x^4*dx/dy + 2y*x^5 - (y*4x^3*dx/dy + x^4) + (y^3* 2*dx/dy + 3y^2*2x) =0

Separating the terms with derivatives:

y^2*5x^4*dx/dy - y*4x^3*dx/dy + y^3* 2*dx/dy = x^4 - 2y*x^5 - 3y^2*2x

dx/dy = (x^4 - 2x^5y - 6xy^2) / (5x^4y^2 - 4x^3y + 2y^3)

7 0

3 years ago

Read 2 more answers

Write 6 less than twice w as an algebraic expression

HACTEHA [7]

6 less than twice w

$2w-6$

5 0

4 years ago

For f(x) = x2 and g(x) = (x − 5)2, in which direction and by how many units should f(x) be shifted to obtain g(x)?

TEA [102]

Right 5 units is the answer.

8 0

4 years ago

Read 2 more answers

Mrs. Jones buys 7 t shirts and 6 hats for $86. The price of each t shirt is $3 more than the price of each hat. How much does Mr

Maslowich

The price of 1 hat is $ 5 and price of 1 t-shirt is $ 8

<em><u>Solution:</u></em>

Let "s" be the price of 1 shirt

Let "h" be the price of 1 hat

<em><u>Given that Jones buys 7 t-shirts and 6 hats for $86</u></em>

Therefore, we can frame a equation as:

price of 1 shirt x 7 + price of 1 hat x 6 = 86

$s \times 7 + h \times 6 = 86$

7s + 6h = 86 ------ eqn 1

<em><u>Also given that The price of each t shirt is $3 more than the price of each hat</u></em>

price of 1 shirt = 3 + price of 1 hat

s = 3 + h -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 2 in eqn 1

7( 3 + h ) + 6h = 86

21 + 7h + 6h = 86

21 + 13h = 86

13h = 86 - 21

13h = 65

From eqn 2,

s = 3 + h = 3 + 5 = 8

Thus price of 1 hat is $ 5 and price of 1 t-shirt is $ 8

8 0

3 years ago