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3 years ago

Solve the equation. If there is no solution, write no solution. 10|n|-3=37.

Mathematics

1 answer:

olga55 [171]3 years ago

6 0

Answer:

C. n=4 or n=-4

Step-by-step explanation:

10lnl-3=37 original problem

+3=+3 add 3 to both sides

10lnl=40 solve that portion

10 divide both sides by 10 to isolate the variable

lnl=4 since n is an absolute value, it is the distance from zero making the solution 4 or -4.

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An iPhone costs 7 times as much as an AirPods. Together they cost $1,200. Find the price of the laptop and iPod.

Mrac [35]

Answer:

Airpods=$150 iPhone=1050

Step-by-step explanation:

$1,200/8=150 150*7=1050

I might be wrong tho

4 0

3 years ago

A tank contains 60 kg of salt and 1000 L of water. A solution of a concentration 0.03 kg of salt per liter enters a tank at the

charle [14.2K]

Answer:

$\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg$

Step-by-step explanation:

Volume of water in the tank = 1000 L

Let y(t) denote the amount of salt in the tank at any time t.

Initially, the tank contains 60 kg of salt, therefore:

y(0)=60 kg

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A solution of concentration 0.03 kg of salt per liter enters a tank at the rate 9 L/min.

$R_{in}$ =(concentration of salt in inflow)(input rate of solution)

$=(0.03\frac{kg}{liter})( 9\frac{liter}{min})=0.27\frac{kg}{min}$

The solution is mixed and drains from the tank at the same rate.

Concentration, $C(t)=\dfrac{Amount}{Volume} =\dfrac{y(t)}{1000}$

$R_{out}$ =(concentration of salt in outflow)(output rate of solution)

$=\dfrac{y(t)}{1000}* 9\dfrac{liter}{min}=0.009y(t)\dfrac{kg}{min}$

Therefore, the differential equation for the amount of Salt in the Tank at any time t:

$\dfrac{dy}{dt}=R_{in}-R_{out}\\\\\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg$

8 0

4 years ago

I NEED ANSWERS RIGHT NOW

Nady [450]

Answer:

The answer is D, $50.09

5 0

3 years ago

Find the area of the shaded region in the graph y=x^2-2

Artist 52 [7]

By applying the concept of <em>definite</em> integral and the given restrictions, we conclude that the area of the <em>shaded</em> region in the graph is - 11/12.

<h3>How to find the area of the shaded region in the graph y = x² - 2</h3>

The area below the curve can be found by using <em>definite</em> integrals, which is defined here in this form:

$I = \int\limits^{1.5}_{0.5} {x^{2}-2} \, dx$ (1)

Now we proceed to calculate the area:

$I = \int\limits^{1.5}_{0.5} {x^{2}} \, dx - 2 \int\limits^{1.5}_{0.5}\, dx$

$I = \frac{x^{3}}{3}|_{0.5}^{1.5} - 2 \cdot x |_{0.5}^{1.5}$

$I = \frac{1.5^{3}-0.5^{3}}{3} - 2 \cdot (1.5 - 0.5)$

$I = -\frac{11}{12}$

By applying the concept of <em>definite</em> integral and the given restrictions, we conclude that the area of the <em>shaded</em> region in the graph is - 11/12.

<h3>Remark</h3>

The statement is incomplete. Complete form is shown below:

Find the area of the shaded region in the graph y = x² - 2, between x = 0.5 and x = 1.5

To learn more on definite integrals: brainly.com/question/14279102

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3 0

2 years ago

3Misty wants to save money to purchase a new bicycle that cost $279. She opens a savings account and deposits $7 per week. Based

Annette [7]

Answer:

it will take at least 10 weeks of saving to buy the bike

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3 years ago