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vagabundo [1.1K]
3 years ago
14

Education among young adults. Choose a young adult (aged 25–29) at random. The probability is 0.10 that the person chosen did no

t complete high school, 0.27 that the person has a high school diploma but no further education, and 0.34 that the person has at least a bachelor’s degree. What must be the probability that a randomly chosen young adult has some education beyond high school but does not have a bachelor’s degree? What is the probability that a randomly chosen young adult has at least a high school education?
Mathematics
1 answer:
yaroslaw [1]3 years ago
8 0

Answer:  a) 0.29, b) 0.9

Step-by-step explanation:

Since we have given that

Probability that a person chosen did not complete high school = 0.10

Probability that the person has a high school diploma but no further education = 0.27

Probability that the person has at least a bachelor's degree = 0.34

So, Probability that a randomly chosen young adult has some education beyond high school but does not have a bachelor's degree is given by

=1- P(a person chosen did not complete high school)-P(the person has a high school diploma but no further education)-P(the person has at least a bachelor's degree)

=1-0.10-0.27-0.34\\\\=0.29

Probability that a randomly chosen young adult has at least a high school education is given by

= 1- P(a person chosen did not complete high school)

=1-0.10\\\\=0.9

Hence, a) 0.29, b) 0.9

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pishuonlain [190]

Answer:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

Step-by-step explanation:

You can do this through synthetic division. It is a shorthand way of dividing polynomials.

First you need to make your divisor equal to zero so you can solve for what goes into the division box:

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The next step is to arrange your polynomials in descending powers. All missing terms, you will put in a zero.

x⁵ - x³ + (-5)   →  x⁵ + 0x⁴- x³ + 0x² + 0x + (-5)

Now you can proceed to synthetic division. Make an upside down division box with the divisor outside and the coefficients of the dividend listed, along with their sign. Leave a space below the divident

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

Next you bring down the first coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

        +1    

Then you multiply it by the divisor and write the product under the next coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>           +2                                   </u>

        +1    

Next add the column and put the sum below it:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2                                   </u>

        +1    +2

Then multiply again and repeat until you reach the last coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2    +4   +6   +12   +24 </u>

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Now that you have your results, add  in the x and their powers. The powers will start with the highest power but 1 less than the dividend. Since the dividend's highest power is 5, then the quotient's highest power will be 4. Then write it in descending order :

+1x⁴    +2x³    +3x²   +6x   +12   +19

Now the last coefficient is your remainder. So your results will be:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

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