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3 years ago

A rectangular balcony is 1 inch wide and 1.75 inches long. If the actual length of the balcony is 7 feet, what is the perimeter

Mathematics

1 answer:

serious [3.7K]3 years ago

6 0

The question is incomplete, complete question is given below.

On the blue print for a house a rectangular balcony is 1 inch wide and 1.75 inches long . if the actual length of the balcony is 7 feet what is the perimeter of the balcony?

Answer:

The perimeter of the balcony is 22 feet.

Step-by-step explanation:

Given,

Actual length = 7 feet

Solution,

In the blue print , length of balcony is 1.75 inches.

The actual length of balcony = 7 feet.

Here we use the unitary method to find out the actual measurement.

$\since\ 1.75\ inches = 7\ feet\\\therefore1\ inch = \frac{7}{1.75} = 4\ feet$

Thus the scale is 1 inch = 4 feet.

On the blue print , the width of the balcony is 1 inch .

So, the actual width = 4 feet

Now,

$Perimeter\ of\ rectangle =2(length+width)$

On substituting the values, we get;

So, the perimeter of the balcony = $2(7+4)$

= $2\times11$

= $22\ feet$

Thus the perimeter of the balcony is 22 feet.

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A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc

aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

$AC^{2} =AB^{2} +BC^{2}$

Substituting the values of BC = 3 and AC = 5, we have,

$5^{2} =AB^{2} +3^{2}$

Squaring the terms, we get,

$25 =AB^{2} +9$

Subtracting both sides by 9, we have,

$16 =AB^{2}$

Taking square root on both sides,

$AB = 4$

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0

3 years ago

A computer can be classified as either cutting dash edge or ancient. Suppose that 86% of computers are classified as ancient.

Leno4ka [110]

Answer:

(a) The probability that both computers are ancient is 0.7396

(b) The probability that all seven computers are ancient is 0.3479

(c) The probability that at least one of seven randomly selected computers is cutting dash edge is 0.6520.

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

Step-by-step explanation:

We know that 86% of computers are classified as ancient. This means, if one computer is chosen at random, there is an 86% chance that it will be classified as ancient.

$P(ancient)=0.86$

(a) To find the probability that two computers are chosen at random and both are ancient you must,

The probability that the first computer is ancient is $P(ancient)=0.86$ and the probability that the second computer is ancient is $P(ancient)=0.86$

These events are independent; the selection of one computer does not affect the selection of another computer.

When calculating the probability that multiple independent events will all occur, the probabilities are multiplied, this is known as the rule of product.

Let A be the event "the first computer is ancient" and B the event "the second computer is ancient".

$P(A\:and \:B)=P(A)\cdot P(B)=0.86\cdot 0.86=0.86^2= 0.7396$

(b) To find the probability that seven computers are chosen at random and all are ancient you must,

Following the same logic in part (a) we have

Let A be the event "the first computer is ancient",

B the event "the second computer is ancient",

C the event "the third computer is ancient",

D the event "the fourth computer is ancient",

E the event "the fifth computer is ancient",

F the event "the sixth computer is ancient", and

G the event "the seventh computer is ancient"

$P(A\:and \:B\:and \:C\:and \:D\:and \:E\:and \:F\:and \:G)=\\P(A)\cdot P(B)\cdot P(C)\cdot P(D)\cdot P(E)\cdot P(F)\cdot P(G) =(0.86)^7=0.3479$

(c) To find the probability that at least one of seven randomly selected computers is cutting dash edge you must

Use the concept of complement. The complement of an event is the subset of outcomes in the sample space that are not in the event.

Let C the event "the computer is cutting dash edge".

Let A the event "the seven computers are ancient".

$P(C)=1-P(A)=1-0.3479=0.6520$

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

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3 years ago

What is the slope of the line ? ( question 1/4 )

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$\huge \rm༆ Answer ༄$

First Consider two points ~ (0 , -3) and (-1 , 0)

Now, use the given formula to calculate slope :

$\sf \dfrac{y2 - y1}{x2 - x1}$

$\sf \dfrac{0 - ( - 3)}{ - 1 - 0}$

$\sf \dfrac{ 0 + 3 }{ - 1}$

$\sf \dfrac{3}{ - 1}$

$\sf - 3$

Therefore, the slope of the graph is -3

$꧁ \: \large \rm{TeeN \: ForeveR } \: ꧂$

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What is 48,100,000,000,000 in scientific notation?

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48,100,000,000,000 in scientific notation is 4.81E+13.

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