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notka56 [123]
3 years ago
5

Is 3/4 closer to 0 or 1?

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

Answer:

It is closer to 1

Step-by-step explanation:

3/4 is 1/4 away from 1, whereas 0 is 3/4 away from 3/4. So, 1 is closer.

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myrzilka [38]

Answer: The answer is (c) parallelogram, because opposite sides are congruent and adjacent sides are not perpendicular.


Step-by-step explanation: The co-ordinates of the vertices of quadrilateral ABCD are given to be A(3,-5), B(5,-2), C(10,-4) and D(8,-7).

The lengths of the sides are as follows -

\textup{AB}=\sqrt{(3-5)^2+(-5+2)^2}=\sqrt{4+9}=\sqrt13,\\\\\textup{BC}=\sqrt{(5-10)^2+(-2+4)^2}=\sqrt{25+4}=\sqrt{29},\\\\\textup{CD}=\sqrt{(10-8)^2+(-4)+7}^2=\sqrt{4+9}=\sqrt{13},\\\\\textup{DA}=\sqrt{(8-3)^2+(-7+5)^2}=\sqrt{25+4}=\sqrt{29}.

Therefore, AB = CD  and  BC = DA.

Also, the slopes of the sides AB(m), BC(n), CD(o) and DA(p) are as follows

m=\dfrac{2+5}{5-3}=\dfrac{3}{2},\\\\n=\dfrac{-4+2}{10-5}=-\dfrac{2}{5},\\\\o=\dfrac{-7+4}{8-10}=\dfrac{3}{2},\\\\p=\dfrac{-7+5}{8-3}=-\dfrac{2}{5}.\\

For two lines to be perpendicular, the product of their slopes should be -1 and for them to be parallel, their slopes must be equal. So, here no two pair of lines are perpendicular. But, m = o and n = p and so, the opposite sides are parallel.   

Since the opposite sides are congruent and parallel, but not perpendicular, so the quadrilateral ABCD is a parallelogram.

Thus, the correct option is (c).

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