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Stells [14]
3 years ago
12

Find the first six terms of the sequence. a1 = -7, an = 2 • an-1

Mathematics
1 answer:
zhenek [66]3 years ago
6 0

Answer:

The first 6 terms are -7,-14,-28,-56,-112,-224

Step-by-step explanation:

The given sequence is defined recursively by:

a_1=-7 and a_n=2(a_{n-1})

When n=2

a_2=2(a_{2-1})

a_2=2(a_{1})

a_2=2(-7)=-14

When n=3

a_3=2(a_{3-1})

a_3=2(a_{2})

a_3=2(-14)=-28

When n=4

a_4=2(a_{4-1})

a_4=2(a_{3})

a_4=2(-28)=-56

When n=5

a_5=2(a_{5-1})

a_5=2(a_{4})

a_5=2(-56)=-112

When n=6

a_6=2(a_{6-1})

a_6=2(a_{5})

a_6=2(-112)=-224

The first 6 terms are -7,-14,-28,-56,-112,-224

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Answer:

The proportion of baby boys in the United States that are born with low birth weight is 0.0495.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

3.41 kg with a standard deviation of 0.55 kg.

This means that \mu = 3.41, \sigma = 0.55

What proportion of baby boys in the United States are born with low birth weight?

This is the pvalue of Z when X = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.5 - 3.41}{0.55}

Z = -1.65

Z = -1.65 has a pvalue of 0.0495

The proportion of baby boys in the United States that are born with low birth weight is 0.0495.

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