4 years ago

I don’t know how to divide 3 and 2 digits

Mathematics

1 answer:

Varvara68 [4.7K]4 years ago

8 0

3.5 think of it as 3.0
C. ——
2.0

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Subtract a4 + 4a²b2 --- 264 from –3a4 + 5a%b2 + 264.

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3 years ago

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lora16 [44]

Answer:

The length of the three sides $5, \sqrt{58} , \sqrt{65}$

The triangle <u>is not</u> a right triangle

Step-by-step explanation:

A = (3, 2) , B = ( 6, 9) , C = (10, 6)

Find the lengths using distance formula.

$distance = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(6-3)^2 + (9-2)^2} = \sqrt{9 + 49 } = \sqrt{58}$

$BC = \sqrt{(10-6)^2 + (6-9)^2} = \sqrt{16 + 9} = \sqrt{25} = 5$

$AC = \sqrt{(3-10)^2+(2-6)^2} = \sqrt{49 + 16} = \sqrt{65}$

Using Pythagoras theorem :

$(Longer \ side)^2 = sum \ of \ square \ of \ two \ other \ sides$

Longest side is AC . So we will check if it satisfies Pythagoras theorem :

$\sqrt{65} = \sqrt{58} + 5^2\\65 = 58 + 25\\$

65 ≠ 58 + 25

So the sides does not satisfy Pythagoras theorem. Hence the triangle is not a right triangle.

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3 years ago

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Answer:

Repeat step 1 for BC or AC

Step-by-step explanation:

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16% of 130 is what number

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130 • .16 = 20.8 or 20 (4/5) or 104/5
Put the answer as 20.8 unless specified otherwise.
.16 is 16%

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4 years ago

Read 2 more answers