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3 years ago

Solve -1/3-2/3 ≥7x+3

Mathematics

1 answer:

goblinko [34]3 years ago

3 0

Answer:

The answer is x≤-4/7

Step-by-step explanation:

hope thia helps

Brainliest????

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What is the gcf of 16 and 25

Salsk061 [2.6K]

The GCF is 1. There is no other number that those numbers have in common.

Hope this helps!!

4 0

3 years ago

Read 2 more answers

Write an equation for the line below

Stells [14]

The answer is : y = -3x + 1

3 0

3 years ago

Given the polynomial 2x3 + 18x2 − 18x − 162, what is the value of the coefficient 'k' in the factored form?2x3 + 18x2 − 18x − 16

s344n2d4d5 [400]

Answer:

$k=3$

Step-by-step explanation:

Let

$f(x)=2x^3+18x^2-18x-162$

We factor 2 to obtain;

$f(x)=2(x^3+9x^2-9x-81)$

We factor the polynomial within the parenthesis by grouping.

$f(x)=2(x^2(x+9)-9(x+9)$

$f(x)=2(x^2-9)(x+9)$

$f(x)=2(x^2-3^2)(x+9)$

We apply difference of two squares on the second factor: $x^2-3^2=(x-3)(x+3)$

$f(x)=2(x+3)(x-3)(x+9)$

We now compare to;

$f(x)=2(x+k)(x-k)(x+9)$

It is now obvious that $k=3$

6 0

3 years ago

Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess

Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill$

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2$

4 0

3 years ago

Read 2 more answers

The median for the given set of six ordered values is 28.5

Alika [10]

X=the missing value

the median is the middle number, but in this case there are two which happens to be 25 and x
so the formula is

25+x/2=31.5
use algebra to solve
25+x=63
x=63-25
x= 38

Therefore, the missing value is 38.

Hope this helped. Let me know if you have any further questions:)

6 0

3 years ago