Answer:
-3/2,collinear.
Step-by-step explanation:
slope of PQ=(0-3)/(2-0)=-3/2
eq. of line PQ is
y-3=-3/2(x-0)
y-3=-3/2 x
or2y-6=-3x
or 3x+2y=6
if R(4,-3) lies on it,then
3(4)+2(-3)=6
12-6=6
or 6=6
which is true.
Hence points P,Q,R are collinear.
and line has aslope=-3/2
First we find the slope by using the slope formula : (y2 - y1) / (x2 - x1)
slope = (y2 - y1) / (x2 - x1)
(0,7)....x1 = 0 and y1 = 7
(8,-2)...x2 = 8 and y2 = -2
now sub...pay attention to ur signs
slope = (-2 - 7) / (8 - 0) = -9/8
now we use y = mx + b
slope(m) = -9/8
u can use either of ur points...(0,7)...x = 0 and y = 7
now sub into ur formula and find b, the y int
7 = -9/8(0) + b
7 = b
so ur equation is : y = -9/8x + 7 <==
Answer: 20 pieces, 72 inches of ribbon
Step-by-step explanation: 6/1.5=4 4x5=20 6x12= 72 inches
Answer:
B and D
Step-by-step explanation:
I think i am right
here the equation of path is -2x-7=y
let us find slope of this line by using y=mx+b
so slope m=-2
now new path is perpendicular to this path.
product of slopes of perpendiculars is -1
so slope of new path is 1/2
now it passes through (-2,-3) with slope 1/2
using y=mx+b to get value of b
-3=1/2(-2) +b
b=-2
plugging m=-1/2 and b=-2 in y=mx + b to get the final equation as
y=(-1/2) x -2 is the equation of new path
