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3 years ago

¿que son los cuadriláteros?

Mathematics

1 answer:

Flura [38]3 years ago

4 0

Answer:

Cuadrilátero solo significa "cuatro lados" (quad significa cuatro, lateral significa lado). Un cuadrilátero tiene cuatro lados, es bidimensional (una forma plana), cerrado (las líneas se unen) y tiene lados rectos.

Un cuadrilátero es un polígono con cuatro aristas y cuatro vértices.

Step-by-step explanation:

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I need help please!!

bekas [8.4K]

Answer:

i hope this helps!

explanation:

part a.) 16 + 5m

part b.) if you walked 15 miles, you would earn $91. work:

16 + 5m

16 + 5(15)

16 + 75

7 0

3 years ago

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Which real-world story is represented by the addition problem (–2) + (–3) = –5?

tangare [24]

The answer is A.

If the submarine descended then it went below, and if it ascended it went above. Therefore:

"Descended 2 miles"= -2

"Then descended another 3 miles"= -3

(-2)+(-3)=-5

Adding two negatives together will give you a bigger negative so the submarine would then be 5 miles below its original location.

6 0

3 years ago

17.25 round up to ones

Irina18 [472]

17.24

Since 7 comes after 5 we need to round to the next number.....18.00

17.24 rounded to ones = 18.00

Hope I helped:P

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3 years ago

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What is the least common multiple of 15 and 6?<br><br> Take notes and show your work.

Mariulka [41]

Hello!

The least common multiple is 3

Hope this helps!

4 0

3 years ago

Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum

const2013 [10]

Answer: The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

$S=\sum_{i=1}^{\infty}15(4)^{i-1}.$

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, $\sum_{i=1}^{\infty}a_i$ is an infinite series, with complex coefficients $a_i$ and we consider the following limit:

$L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.$

Then, the series will be convergent if L < 1 and divergent if L > 1.

For the given series, we have

$a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.$

So, the limit is given by

$L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.$

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0

3 years ago

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