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2 years ago

When a particular mass-spring system is started by stretching the spring 3 cm, one complete oscillation takes 4 seconds.

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

4 0

Answer:

A. 5.16 s.

B. 5.66 s.

Step-by-step explanation:

For a simple harmonic motion,

T = 2pi (sqrt * (l/g))

Given:

L1 = 3 cm

T1 = 4 s

L2 = 5 cm

T2 = ?

4 = 2pi*sqrt(3/g)

g = 7.4

At, L2,

T2 = 2pi*sqrt(5/7.4)

= 5.16 s.

M1 = M1

M2 = 2*M1

For a simple harmonic motion,

T = 2pi (sqrt * (m/k))

4 = 2pi (sqrt * (M1/k))

M1/k = 0.405

Inputting the above values,

T2 = 2pi (sqrt * (2*M1/k))

= 2pi (sqrt * (2 * 0.405))

= 5.66 s.

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