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masha68 [24]
3 years ago
12

a tiler wants to tile a rectangular wall which measures 4m by 2.5m. Each tile measures 16cm by 10cm. How many tiles will he need

for the wall?

Mathematics
1 answer:
Aloiza [94]3 years ago
4 0
There are 100 cm in 1 meter. the dimensions are 400cm by 250cm. depending on which way you turn them, they will fit better. if you take 400 divided by 16, you will have a row of 25 wide and if you divide 250 by 10, you will have a length of 25. you now have 25 rows of 25. 25x25 is 625 tiles.
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Ratio = 8/7

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Read 2 more answers
The question is in the pic please be specific
vichka [17]
Box 1) (LxW) 20x6=120
box 2) (LxW) 15x4=60
box 1 cost) (size of box x price of box) 120x1.25=150
box 2 cost) (size of box x price of box) 60x1.25=75
subtract 150 and 75 to get 75

answer: the company is saving $75 by choosing to make 50 of box 2 instead of 50 of box 1

hope this makes sense comment if you need more explanation
8 0
3 years ago
The length of a rectangular field is 4 meters less than 5 times the breadth of the hall. What is the length, if the breadth is b
vlabodo [156]
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4 0
2 years ago
Y-2=4(x+3) what the slope intercept
Kryger [21]

Answer:

Slope intercept form: y = 4x + 14

Slope: 4

Y-intercept: 14

Step-by-step explanation:

y - 2 = 4(x + 3)

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y - 2 = 4x + 12

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3 0
2 years ago
Please help me with this.
OLga [1]

Swapping rows alters the sign of the determinant:

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}

Multiplying a single row by a scalar scales the determinant by the same amount:

\begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix} = -2 \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix}

Then

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = -(-2) \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix} = 2\times(-6) = \boxed{-12}

8 0
2 years ago
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