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zysi [14]
3 years ago
6

Hi please help me solve this questions thanks

Mathematics
1 answer:
ioda3 years ago
4 0
Perimeter=2(length(x)+width(y))

16=2(l+w)

16=2(5+3)

5+5+3+3=16

length (2 sides) =5+5=10
width (2 sides) =3+3=6



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Daniela bought a square carpet for her dining room of an area of 9 ft squared. The space of of the dining room is approximately
Anna [14]

Answer:

yes there is because the carpet is 9ft squared but the dinning room floor area is 3.5*3.5= 12.25 so there is still space left even when carpet is put down.

5 0
4 years ago
Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc
DerKrebs [107]

we are given

differential equation as

y'''-9y''+20y'=0

we are given

y=e^{rx}

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

y'=re^{rx}

Second derivative is

y''=r*re^{rx}

y''=r^2e^{rx}

Third derivative is

y'''=r^2*re^{rx}

y'''=r^3e^{rx}

now, we can plug these values into differential equation

and we get

r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0

now, we can factor out common terms

e^{rx}(r^3 -9r^2 +20r)=0

we can move that term on right side

(r^3 -9r^2 +20r)=0

now, we can factor out

r(r^2 -9r +20)=0

r(r-5)(r-4)=0

now, we can set them equal

r=0

r-5=0

r=5

r-4=0

r=4

so, we will get

r=0,4,5...............Answer

4 0
4 years ago
The square rootof which number is rational a7. b 1.96. c. 0.04. d. 13​
artcher [175]

Answer:

B and C

Step-by-step explanation:

We need to find which one of these numbers is a perfect square. We know 7 and 13 can be eliminated since they're prime numbers so they can't be perfect squares. B and C are both perfect squares so that's the answer.

3 0
4 years ago
Read 2 more answers
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
Answer all parts of number 1 thank you.
Scorpion4ik [409]

Hi!

1.)

a:A u B=

(1.0. - 5. \frac{1}{2} .e)

(The same elements are written once.)

b:A u C

(1.0 - 5. \frac{1}{2} .2)

c:B u C

( - 5 .1.e.0.2)

Note:I used dots to mean commas .

Good work!

7 0
2 years ago
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