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elixir [45]
3 years ago
8

What is the range of the function represented by the table of values below?

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0
The range is the interval of y values.
Smallest y values is -9 and the highest y values is 9.
So the range is -9 \leq y \leq 9
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AABC ~ADEF<br> F<br> 21<br> D<br> B<br> N<br> 28<br> E<br> C<br> Solve for N.<br> 28 = ☆<br> N=[?]
sergij07 [2.7K]

Answer:

N = 3

Step-by-step explanation:

\frac{28}{4}  =  \frac{21}{N}  \\  \\ 28N = 21 \times 4 \\ 28N = 84 \\  \\ N =  \frac{84}{28}  \\  \\ N = 3

I hope I helped you^_^

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Read 2 more answers
Need help with these two questions
WITCHER [35]

Answer:


Step-by-step explanation:

Answer:(A)= (-x^11)/(y^7)

(B)= (1/12xy^5)


Step-by-step explanation:

(A) (3x^3y^-2)(-2x^-3y^2)^-5/(6x^7y^-5)

[(3x^3y^-2)(-2x^15y^-10)]/(6x^7y^-5)

(6x^18y^5)/(-6x^7y^12)

(-6x^11)/(6y^7)

(-x^11)/(y^7)

(B) [(12x^-3y^5)/(x^-4)]^-1

(1/12xy^5)

7 0
3 years ago
The vertical asymptote is x = ?<br>y=a/x-h +k​
gtnhenbr [62]

Answer:

x=a/(y-k)+h

Step-by-step explanation:

y-k=a/(x-h)

(y-k)(x-h)=a

xy-hy-kx+kh=a

xy-kx=a+hy-hk

x(y-k)=a+h(y-k)

x=a/(y-k)+h

4 0
3 years ago
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