The answer to this is C. (28,10) and (22,2).
Answer:
2" by 3.467"
Step-by-step explanation:
You can write the proportion ...
(print length)/(print unit) = (floor length)/(floor unit)
print length = (print unit)×(floor length)/(floor unit)
For floor length = 15', ...
print length = (1")(15')/(7.5') = 2"
For floor length 26', ...
print length = (1")(26')/(7.5') = (52/15)" = 3 7/15" ≈ 3.467"
The office will be approximately 2" by 3.467" on the drawing.
2x - 3y + 6 = 0
<u> - 6 - 6</u>
2x - 3y = -6
2x - 2x - 3y = -6 - 2x
<u>-3y</u> = <u>-6 - 2x</u>
-3 -3
y = 2 + ²/₃x
Answer:
7/6
Step-by-step explanation:
in order for it to perpendicular then its need to be the negative reciprocal of it, so you flip the sign making it positive and do the opposite of the slope like for ex if it was 1/2 it would have been 2
![\bf \begin{array}{cccccclllll} \textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\ \textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\ y&=&{{ k}}&\cdot&x \\ && y={{ k }}x \end{array}\\\\ -----------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bcccccclllll%7D%0A%5Ctextit%7Bsomething%7D%26%26%5Ctextit%7Bvaries%20directly%20to%7D%26%26%5Ctextit%7Bsomething%20else%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Ctextit%7Bsomething%7D%26%3D%26%7B%7B%20%5Ctextit%7Bsome%20value%7D%7D%7D%26%5Ccdot%20%26%5Ctextit%7Bsomething%20else%7D%5C%5C%20%5Cquad%20%5C%5C%0Ay%26%3D%26%7B%7B%20k%7D%7D%26%5Ccdot%26x%0A%5C%5C%0A%26%26%20%20y%3D%7B%7B%20k%20%7D%7Dx%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C)
![\bf % inverse proportional variation \begin{array}{llllll} \textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\ \textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\ y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x} \\ &&y=\cfrac{{{ k}}}{x} \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%0A%25%20inverse%20proportional%20variation%0A%5Cbegin%7Barray%7D%7Bllllll%7D%0A%5Ctextit%7Bsomething%7D%26%26%5Ctextit%7Bvaries%20inversely%20to%7D%26%5Ctextit%7Bsomething%20else%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Ctextit%7Bsomething%7D%26%3D%26%5Ccfrac%7B%7B%7B%5Ctextit%7Bsome%20value%7D%7D%7D%7D%7B%7D%26%5Ccfrac%7B%7D%7B%5Ctextit%7Bsomething%20else%7D%7D%5C%5C%20%5Cquad%20%5C%5C%0Ay%26%3D%26%5Ccfrac%7B%7B%7B%5Ctextit%7Bk%7D%7D%7D%7D%7B%7D%26%5Ccfrac%7B%7D%7Bx%7D%0A%5C%5C%0A%26%26y%3D%5Ccfrac%7B%7B%7B%20%20k%7D%7D%7D%7Bx%7D%0A%5Cend%7Barray%7D)
now... let's see
"<span>m varies directly as the square root of y, inversely as p², and directly as n"
</span>
![\bf m=\cfrac{k\sqrt{y}\cdot n}{p^2}](https://tex.z-dn.net/?f=%5Cbf%20m%3D%5Ccfrac%7Bk%5Csqrt%7By%7D%5Ccdot%20n%7D%7Bp%5E2%7D)
<span>
now, let's quadruple "y", multiply "n" by 5 and "p" by 3
</span>