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sladkih [1.3K]
3 years ago
15

Write the indicated event in set notation.When four coins are tossed, the first three tosses come up the same.[Hint: when four c

oins are tossed, the following 16 outcomes are possible:HHHH HHHT HHTH HHTTHTHH HTHT HTTH HTTTTHHH THHT THTH THTTTTHH TTHT TTTH TTTT ]a. (HHH, TTT) b. (HHHT, TTTH) c. (HHHT, TTTH, HTTT, THHH) d. (HHHH, HHHT, TTTH, TTTT)
Mathematics
1 answer:
artcher [175]3 years ago
8 0

Answer:

Outcomes = \{HHHH, HHHT,TTTH, TTTT\}

Step-by-step explanation:

Given

S = \{HHHH, HHHT, HHTH, HHTT,HTHH, HTHT, HTTH, HTTT, THHH, THHT,

THTH, THTT,TTHH, TTHT, TTTH, TTTT\}

Required

The outcomes where the first three tosses are the same

To do this, we list out the outcomes that the first three are HHH or TTT.

So, we have:

Outcomes = \{HHHH, HHHT,TTTH, TTTT\}

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The answer would be
3x² - x + 3
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hram777 [196]
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What are two numbers that add up to 70 without regrouping?
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3 years ago
L varies directly with the square of Z. L is 12 when Z is 2. Find the value of L when Z is 4.
kow [346]

Answer:

L = 48

Step-by-step explanation:

Given that L varies directly with Z² , then the equation relating them is

L = kZ² ← k is the constant of variation

To find k use the condition L = 12 when Z = 2 , then

12 = k × 2² = 4k ( divide both sides by 4 )

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L = 3Z² ← equation of variation

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7 0
3 years ago
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
4 years ago
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