Octagon, stop sign.
Eight isoscles triangles. It looks like we're told the side is 9.9 and the height to the side (also called the apothem) is 12.
So each isosceles triangle has area (1/2)(9.9)(12) and we have eight of them,
area = 8(1/2)(9.9)(12) = 475.2
Answer: 475.2
Usually we wouldn't be told 9.9 -- this is the baby version. We know each of those isoscles triangles has unique angle 360/8=45 degrees, so the apothem and half the side of the octagon are a right triangle with acute angle 22.5 degrees.
The area of the right triangle with long leg 12, short leg x,
tan 22.5 = x/12 or
x = 12 tan 22.5
Twice that is what we're told is 9.9; let's check:
2x = 24 tan 22.5 = 9.941125496954282
The area of the little right triangle is
(1/2) 12 × 12 tan 22.5
and there are 16 of these
16 (1/2) 12 × 12 tan 22.5 ≈ 477.174
Answer:
5000(1+0.41)^5
Step-by-step explanation:
did the khan academy
Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q = 
- 
= 0
Sum of angles in a triangle = 
<P + <Q + <S =
048° + 0 + <S =
+ <S =
<S = -
= 
<S =
Applying the Sine rule,
= 
= 
=
= 
= 
⇒ y = 
= 12.703
y = 12.70 km
=
=
=
⇒ x = 
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
I don't think those two expressions would even be equal unless w = 0. You can't just add in a 2 from nowhere.
Answer:
decreasing increasing decreasing function
