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Debora [2.8K]
2 years ago
12

Every 24 hours, the earth rotates 360° about its axis. How

Mathematics
1 answer:
Usimov [2.4K]2 years ago
8 0

360 degrees / 24 hours = 15 degrees per hour


150 degrees / 15 degrees per hour = 10 hours


Answer: 10 hours

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Giving brainliest.. and 25 points
siniylev [52]

Answer:

Alright well the simplified system is arbitrary solution of the original system of equation

a1 = - 15

an = - 15/4 Hope this helps have nice day :)

Step-by-step explanation:


5 0
3 years ago
A diameter of a circle is 12 inches. What's the distance when rotate 3 circle ?
ehidna [41]

Answer:

36π inches which is 113.10 inches to the nearest hundredth

Step-by-step explanation:

The circumference = 12 * π

Rotating 3 times  the distance moved is 3 * 12π.

3 0
3 years ago
6. Write an equation of a line parallel to y = 3x + 9 and goes through the point (-1,5).
lisabon 2012 [21]

Answer: The equation parallel to the line is y=3x+8

Step-by-step explanation: Parallel lines have the same gradients, wr have a gradient for the above line which 3. The standard formula for the linear equation is y=mx+c

We have to calculate c since we have x and y.

y=mx+c

5= 3(-1)+c

c=8

The equation become y=3x+8

4 0
3 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
it was found that out of 45 girls,10 joined singing but not dancing and 24 joined singing.How many joined both. options: A: 21 B
katrin [286]

Answer:

answer is 24

out of 45,

24+10=singing

only 24=dancing

so 24 girls joined both

3 0
3 years ago
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