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2 years ago

12

Every 24 hours, the earth rotates 360° about its axis. How

1 answer:

Usimov [2.4K]2 years ago

8 0

360 degrees / 24 hours = 15 degrees per hour

150 degrees / 15 degrees per hour = 10 hours

Answer: 10 hours

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What is the area of a sector with a central angle of 2π7 radians and a diameter of 40.6 mm?

Gennadij [26K]

Answer:

184.85 square mm

Step-by-step explanation:

The area of a sector of a circle is $\frac{1}{2} r^{2} \theta$ , where r is the radius and $\theta$ is the angle in radians subtended by the arc at the centre of the circle.

Since, diameter = 40.6 mm

So, radius(r)=20.3 mm and $\theta$ = $\frac{2 \pi}{7}$ radians

So, area of sector= $\frac{1}{2} r^{2} \theta$

= $\frac{1}{2} (20.3)^2 (\frac{2 \times 3.14}{7})$

=184.85 square mm

5 0

4 years ago

Select the values of x that make the inequality true <br><br><br> x > -3

arlik [135]

a and c, the further you go down the negative number line, the lower the value of the number is so -1 and 0 are bigger

5 0

3 years ago

Read 2 more answers

Help with cal 2 exercise involving integrals?

zhannawk [14.2K]

$\displaystyle\int\frac{\sqrt{x^2+1}}x\,\mathrm dx=\int\frac{\sqrt{\tan^2B+1}}{\tan B}\sec^2B\,\mathrm dB$

$\tan^2B+1=\sec^2B$

$\sqrt{\sec^2B}=\sec B$ (provided that $\sec B>0$ )

Then

$\dfrac{\sec B}{\tan B}\cdot\sec^2B=\dfrac{\sec^2B}{\tan B}\cdot\sec B$

(just moving around a factor of $\sec B$ )

$\dfrac{\sec B}{\tan B}\cdot\sec^2B=\dfrac{\sec^2B}{\tan^2B}\cdot\sec B\tan B$

(multiply by $\dfrac{\tan B}{\tan B}$ )

8 0

3 years ago

Tom has a 10 gallon fish tank that he wants to fill with neon tetra

skelet666 [1.2K]

The equation representing the minimum and maximum number of fishes which would fit into the tank is : 5 ≤ x ≤ 9

From the table given ;

Method 2 will allow the maximum number of fish = 9
Method 1 will allow the minimum number of fish = 5

To represent the maximum and minimum number of fish that will fit into the tank;

We could use an inequality expression to represent these range :

Let x represent the Number of fishes that would fit into the tank :

Minimum ≤ x ≤ maximum

Therefore, the equation can be written thus :

5 ≤ x ≤ 9

Learn more : brainly.com/question/24566347

4 0

3 years ago

What are the next 3 numbers in this pattern of integers -2, -1, -1, 0, -1, 1, -2

sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

Let $a_{1}=-2$

$a_{2}=-1$

$a_{3}=a_{1}-a_{2}$

$=-2-(-1)$

$=-2+1$

Therefore $a_{3}=-1$

$a_{4}=a_{2}-a_{3}$

$=-1-(-1)$

$=-1+1$

Therefore $a_{4}=0$

Similarly we have $a_{5}=-1$ , $a_{6}=1$ , $a_{7}=-2$

The general form to the given pattern is

$a_{n}=a_{n-2}+a_{n-1}$ for $n={\{1,2,3,4,5,6,7,8,9,10}\}$

Therefore to find the $a_{8},a_{9},a_{10}$

Put n=8 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{8}=a_{8-2}-a_{8-1}$

$=a_{6}-a_{7}$

$=1-(-2)$

$a_{8}=3$

Put n=9 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{9}=a_{9-2}-a_{9-1}$

$=a_{7}-a_{8}$

$=-2-(3)$

$a_{9}=-5$

Put n=10 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{10}=a_{10-2}-a_{10-1}$

$=a_{8}-a_{9}$

$=3-(-5)$

$a_{10}=8$

Therefore the next 3 numbers are 3,-5,8

4 0

3 years ago