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kvv77 [185]
3 years ago
8

In attempting to understand how nature works, scientists seek ultimately for the... Question 9 options: A. final proof B. facts

C. truth D. total control of nature E. most likely explanation
SAT
1 answer:
kaheart [24]3 years ago
4 0
It’s either A or E most scientist try to come up with a logical explanation when it comes to nature and why it happens in nature I’m going to say it’s E because they can’t just have a final answer there more and likely going to come up with a rational person explanation
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Which of these is important to interpreting scientific information?
Marrrta [24]

Answer:

D Reasoning.

Explanation:

The key here is that it involves scientific investigation. This must be done without bias or personal history, which only serve to taint the results. Mythology is a religion and has no place in the interpretation of scientific results.

5 0
3 years ago
Students in a statistics class are conducting a survey to estimate the mean number of units students at their college are enroll
Andrew [12]

Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed <em>95% confidence interval</em>, with 49 - 1 = <em>48 df</em>, is t = 2.0106.

Hence:

\overline{x} - t\frac{s}{\sqrt{n}} = 12.2 - 2.0106\frac{1.6}{\sqrt{49}} = 11.7

\overline{x} + t\frac{s}{\sqrt{n}} = 12.2 + 2.0106\frac{1.6}{\sqrt{49}} = 12.7

The 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

More can be learned about the t-distribution at brainly.com/question/16162795

4 0
2 years ago
What is the value of x? enter your answer in the box. X = note: image not drawn to scale. Triangle g e h with segment e d such t
Elodia [21]

Triangle GED and triangle DEH are similar triangles with a common side length DE

The value of x is 24

<h3>How to calculate the value of x</h3>

To calculate x, we make use of the following equivalent ratio

GD : DH = EG : EH

Substitute known values

x + 4 : 35= 44.8 : 56

Express the ratio as fraction

\frac{x + 4}{35}= \frac{44.8}{ 56}

Evaluate the quotient

\frac{x + 4}{35}= 0.8

Multiply both sides by 35

x + 4= 28

Subtract 4 from both sides

x= 24

Hence, the value of x is 24

Read more about similar triangles at:

brainly.com/question/12687306

8 0
2 years ago
A good rule of thumb is to design the horizontal stabilizer so that its area is about 1/6 to 1/8 of the area of the wing. If the
mars1129 [50]

Answer:

Answer:

Stabilizer with area = 14 cm².

Step-by-step explanation:

Area of the wing = 101.25 cm²

Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.

1/6 of the area of wing = \frac{1}{6} \times 101.25 = 16.87561×101.25=16.875

1/8 of the area of wing = \frac{1}{8} \times 101.25 = 12.65681×101.25=12.656

This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²

Therefore, area of a good stabilizer design from the given options would be 14 cm²

7 0
3 years ago
Read 2 more answers
At a large corporation, the distribution of years of employment for the employees has mean 20.6 years and standard deviation 5.3
Cerrena [4.2K]

Answer:

Yes

Explanation:

The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma}\\\\where\  \mu=mean.\sigma=standard\ deviation,  x=raw\ score.\\\\For\ a \ sample\ size\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

For a normal distribution with a mean of μ and standard deviation σ, For any sample size (n) drawn from this population, the sample mean is normally distributed, with mean \mu_x=\mu and standard deviation \sigma_x=\frac{\sigma}{\sqrt{n } } \\\\.

Hence given that a mean of μ = 20.6 years and standard deviation σ = 5.3 years, for a sample size of 100:

mean \mu_x=\mu=20.6\ years and standard deviation \sigma_x=\frac{\sigma}{\sqrt{n } } =\frac{5.3}{\sqrt{100} }=0.53\ years \\\\.

7 0
3 years ago
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