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Gekata [30.6K]
4 years ago
9

13.2)

Mathematics
1 answer:
Neko [114]4 years ago
4 0

Answer:

390

Step-by-step explanation:

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carly walks 30 feet in seven seconds. At this rate, how many minutes will it take for carly to walk a mile if there are 5,280 fe
LenaWriter [7]

Answer:

20.53 minutes

Step-by-step explanation:

Speed = Distance/Time = 30/7

Time = Distance / Speed

= 5280/30/7

= 1232 seconds / 60 = 20.53 minutes

Answered by Gauthmath

4 0
3 years ago
The length of a rectangular garden is 3 yd less than twice its length. The perimeter of the garden is 78 yd. What are the width
Alenkasestr [34]

Complete question :

Answer:

Width = 14 yards ; length = 25 yards

Step-by-step explanation:

Given that :

The length of a rectangular garden is 3 yd less than twice its length. The perimeter of the garden is 78 yd. What are the width and length of the garden?

Width of garden (W) = w

Lenght of garden (L) = 2w - 3

Perimeter of a rectangle : 2 (L + W)

2(2w - 3 + w) = 78

2(3w - 3) = 78

6w - 6 = 78

6w = 78 + 6

6w = 84

w = 14 yards

Length = 2(14) - 3

Length = 28 - 3 = 25 yards

3 0
3 years ago
Rico can walk 3 miles in the same amount of time that Donna can walk 2 miles. Rico walks at a rate 2 miles per hour faster than
tatyana61 [14]

Answer:

13

Step-by-step explanation:

Donna's Rate is R

Rico's Rate is R+2

\frac{R}{R+2}=\frac{2}{3}

Cross-Multiply

2(R+2)=32

2R+4=3R

4=R

Donna's Rate is R=4

Rico's Rate is R+2=6

\frac{6(130)}{60} = \frac{130}{10}=13

5 0
3 years ago
3. In the diagram, what is the value of x? A. 98° B. 82° C. 108° D. 78°
jek_recluse [69]
Where’s the diagram...?
6 0
4 years ago
Resolve into partial fractions<br><br>​
lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

1)

\frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A}{2 - x}  +  \frac{B}{x - 3}  \\  \\  \therefore \:  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)}   \\  \\ \therefore \:  11 + x = Ax - 3A + 2B - Bx \\  \\  \therefore \: 11 + x = - 3A  + 2B  + Ax -  Bx\\  \\  \therefore \: 11 + x = - 3A  + 2B  + (A - B)x \\  \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\  \therefore \: A  =  B  +  1.....(1) \\  \\  -  3A  + 2B = 11....(2) \\  from \: eq \: (1) \: and \: (2) \\  - 3(B  +  1) + + 2B = 11 \\  \\ - 3B   - 3  + 2B = 11 \\  \\  - B = 11 + 3 \\  \\ B =  - 14  \\ A  =   - 14 +  1 =  - 13 \\  \\  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{ - 13}{2 - x}  +  \frac{ - 14}{x - 3} \\  \\ \frac{11 + x}{(2 - x)(x - 3)}  = -   \frac{ 13}{2 - x}   -  \frac{ 14}{x - 3}

2)

\frac{12x + 11}{x^2 +x - 6}

=\frac{12x + 11}{x^2 +3x-2x - 6}

=\frac{12x + 11}{x(x +3) -2(x +3)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A}{(x +3)}+\frac{B}{(x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A(x-2)+B(x+3)}{(x-2)(x+3)}

\therefore 12x + 11 = A(x-2)+B(x+3)

\therefore 12x + 11 = Ax-2A+Bx+3B

\therefore 12x + 11 = Ax+Bx-2A+3B

\therefore 12x + 11 = (A+B) x-2A+3B

Equating like terms on both sides:

A + B = 12\implies A = 12-B... (1)

- 2A + 3B = 11... (2)

Solving equations (1) & (2), we find:

A = 5, B = 7

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{5}{(x +3)}+\frac{7}{(x - 2)}

3 0
3 years ago
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