Answer:
Explanation:
As the car Started from rest means that Initial Velocity "Vi = 0 m/s" and final Velocity is given "Vf = 42m/s". Time is given "t = 6.2s"
Acceleration is required a =?
Use Formula;; a = ![\frac{Vf-Vi}{t}](https://tex.z-dn.net/?f=%5Cfrac%7BVf-Vi%7D%7Bt%7D)
a = ![\frac{42-0}{6.2}](https://tex.z-dn.net/?f=%5Cfrac%7B42-0%7D%7B6.2%7D)
a = 6.7741 m/s² ≈ 6.8 m/s²
Mark me as brainliest if you got it...
Newton's second law states that
(Force is mass times acceleration). Out of the given options, “a 10 kg ball thrown with a 50 Newton force”, an example have the greatest acceleration.
<u>Explanation:
</u>
To do the calculation, we already have the formula given derived from Newton’s second law of motion. To know the acceleration, we can simply modify the formula as,
![\text { Force }=\text { mass } \times \text { acceleration }](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Force%20%7D%3D%5Ctext%20%7B%20mass%20%7D%20%5Ctimes%20%5Ctext%20%7B%20acceleration%20%7D)
![\text {acceleration}=\frac{\text {Force}}{\text {mass}}](https://tex.z-dn.net/?f=%5Ctext%20%7Bacceleration%7D%3D%5Cfrac%7B%5Ctext%20%7BForce%7D%7D%7B%5Ctext%20%7Bmass%7D%7D)
For the 10kg ball threw in 50N, we have mass = 10 kg and Force = 50 N
Acceleration = ![\frac{50}{10}=5 \mathrm{m} / \mathrm{s}^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B50%7D%7B10%7D%3D5%20%5Cmathrm%7Bm%7D%20%2F%20%5Cmathrm%7Bs%7D%5E%7B2%7D)
Similarly for 1 kg ball threw in 0.5N, substituting the values, we get
,
Acceleration = ![\frac{0.5}{1} = 0.5 \mathrm{m} / \mathrm{s}^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B0.5%7D%7B1%7D%20%3D%200.5%20%5Cmathrm%7Bm%7D%20%2F%20%5Cmathrm%7Bs%7D%5E%7B2%7D)
For launching 50kg student by catapult of 100N,
acceleration = ![\frac{100}{50}=2 m / s^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B100%7D%7B50%7D%3D2%20m%20%2F%20s%5E%7B2%7D)
For accelerating 500 kg car in 1000N engine,
acceleration = ![\frac{1000}{500} = 2 m / s^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1000%7D%7B500%7D%20%3D%202%20m%20%2F%20s%5E%7B2%7D)
WHY HELLO THERE! THE PREFIX NANO MEANS ''1 BILLIONTH OF'' AND IS USED MOSTLY WHEN TALKING ABOUT THE METRIC SYSTEM. HOPE THIS HELPED!!!!!
Answer:
Free-fall is defined as the movement where the only force acting on an object is the gravitational force.
By the second Newton's law, we have that:
F = m*a
Where F = Force, m = mass, a = acceleration.
We can write this as:
a = F/m
And the gravitational force can be written as:
F = (G*M/r^2)*m
Where G is the gravitational constant, M is the mass of the Earth in this case, and r is the distance between both objects (the center of the Earth and the free-falling object)
As the radius of the Earth is really big, the term inside the parentheses is almost constant in the region of interest, then we can write:
G*M/r^2 ≈ g
And the gravitational force is:
F = g*m
And by the second Newton's law we had:
a = F/m = (g*m)/m = g
a = g
Then the acceleration does not depend on the mass of the object.
Then the thing that is common among the free-falling objects is the vertical acceleration.