Question

A motorbike uses petrol and oil mixed in the ratio 13:2

Answer 1

Answer:

Part A) $26\ liters$ of petrol and $4\ liters$ of oil

part B) $3.25\ liters$ or $3,250\ ml$ of petrol

Step-by-step explanation:

Part A) How much of each is there in 30 liters of mixture ?

Let

x-----> the amount of liters of petrol

y----> the amount of liters of oil

we know that

$\frac{x}{y}=\frac{13}{2}$

$x=\frac{13}{2}y$ -----> equation A

$x+y=30$ ---> equation B

substitute equation A in equation B

$\frac{13}{2}y+y=30$

$\frac{15}{2}y=30$

$y=30*2/15=4\ liters$

Find the value of x

$x=\frac{13}{2}(4)=26\ liters$

Part B) How much petrol would be mixed with 500 ml of oil?

Convert ml to l

$500\ ml=0.50\ l$

we know that

using proportion

$\frac{13}{2}=\frac{x}{0.5}\\ \\x=13*0.5/2\\ \\x=3.25\ l$