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arlik [135]
3 years ago
9

Which of the following shows the figure rotated 90 degrees counterclockwise around the origin and then reflected across the x-ax

is?​

Mathematics
2 answers:
Tom [10]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Transformation rule : The coordinates change by the rule when the figure rotate 90 degrees about the origin is given by

(x,y)\righatrrow (-y,x)

Transformation rule: When the figure reflected across x- axis then the coordinates change by the rule

(x,y)\rightarow (x,-y)

The given figure cut x - axis at x=3

The coordinates (3,0).

After 90 degrees rotation about origin the coordinates becomes (0,3).

After reflection across x- axis , the coordinates becomes (0,-3).

Only in first figure, there is (0,-3) .

Hence, the option A is true.

olchik [2.2K]3 years ago
6 0

Answer:

The first one

Step-by-step explanation:

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Triangle ABC has vertices A0,0), B(3,2)and C(0,4). The triangle may be classified as
lawyer [7]

Answer:

aceite triangle

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because when you put it in a graph all ángles are acitr

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Help will give brainliest!!!!!!
sashaice [31]

Answer:

2.5

type A/B

Step-by-step explanation:

10/2.5=4

15/6=2.5

18/7.2=2.5

7 0
3 years ago
An experiment was conducted to investigate whether there is a difference in mean bag strengths for two different brands of paper
Elanso [62]

Answer:

A two-sample t-test for a difference between sample means

Step-by-step explanation:

<u>Explanation</u>:-

A random sample of 50 bags from each of Brand X and Brand Y was selected

Given two sample sizes n₁ and n₂

Each bag was held from its rim, and one-ounce weights were dropped into the bag one at a time from the same height until the bag ripped

mean of ounces the first sample = x⁻

mean of the  second sample =y⁻

Given data one-ounce weights were dropped into the bag one at a time from the same height until the bag ripped

Standard deviation of the first sample = S₁

Standard deviation of the second sample = S₂

Now we use t - distribution for a difference between the means

t = \frac{x^{-}  -y^{-} }{\sqrt{S^{2}(\frac{1}{n_{1} }  +\frac{1}{n_{2} } } }

where

S^{2} = \frac{n_{1} S_{1} ^{2} +n_{2}S_{2} ^{2}  }{n_{1} +n_{2} -2 }

Degrees of freedom γ = n₁ +n₂ -2

3 0
3 years ago
I need to fill out the blanks
zzz [600]

Answer:

1. <u>14x</u> and <u>7</u> and <u>9x</u> and <u>3</u>

2. <u>0x</u>

3. <u>4</u>

Step-by-step explanation:

Step 1: Distribute

First, multiply 7 by 2x and 1 to get 14x and 7. Then multiply -3 by 3x and 1 to get -9x and -1

Step 2: Combine like variable terms

Combine 14x, -5x, and -9x, to get 0x.

Step 3: Combine like constant terms

Combine 7 and -3, to get 4.

6 0
3 years ago
Is the ordered pair a solution of y ≥ 2x − 5? a. (3, 1) b. (1, −4)
Deffense [45]

Answer:

a. Yes

b. No

Step-by-step explanation:

To find if an ordered pair is a solution to the inequality, substitute its x and y values for the x and y in the inequality and solve. If the equation is true, then it is a solution. If it is not, then it is not a solution.

1) First, substitute the x and y values of (3, 1) into the inequality. So, substitute 3 for x and 1 for y:

1 \geq 2(3)-5\\1\geq 6-5\\1\geq 1

1 is greater than or equal to 1, so (3,1) is a solution.

2) Second, do the same with the point (1, -4). Substitute 1 for x and -4 for y:

-4\geq 2(1)-5\\\\-4\geq 2-5\\-4\geq -3

However, -4 is not greater than or equal to -3, thus (1, -4) is not a solution.

4 0
3 years ago
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