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Naily [24]
3 years ago
7

Find the unit rate with the numbers 12 and one and one half

Mathematics
1 answer:
kati45 [8]3 years ago
4 0

Answer:

The value of the unit rate is 8

Step-by-step explanation:

we know that

To calculate the unit rate simply divide the first number by the second number

so

12:1\frac{1}{2}

Convert mixed number to an improper fraction

1\frac{1}{2}=1+\frac{1}{2}=\frac{1*2+1}{2}=\frac{3}{2}

substitute in the expression above

12:\frac{3}{2}=\frac{24}{3}=8

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I really need help with this question! Please help me!!!
Dafna11 [192]

Answer:

42°

Step-by-step explanation:

AD bisects ∠CAB, which means it splits ∠CAB into two equal parts. ∠CAB equals 84°. 84° ÷ 2 = 42°.

7 0
4 years ago
Are these answers correct? If not, what would the answers be?
Ludmilka [50]
Yes you have the correct answers for each of the four problems. Nice work.

For anyone curious,
rd = removable discontinuity
id = infinite discontinuity
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7 0
3 years ago
If 3a + b + c = -3, a+3b+c = 9, a+b+3c = 19 find a*b*c
VashaNatasha [74]

Answer:

a=-4

b=2

c=7

so therefore a*b*c=-4*2*7

5 0
3 years ago
Simplify the given expression, using only positive exponents. Then complete the statements that follow.
Alenkinab [10]

Answer:

lol but where is the main question

7 0
3 years ago
Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me
Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

V= \pi r^2 h

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr

So finding the partial derivatives we get

dV =\pi r^2 dh + \pi 2r h dr

dV =\pi r^2 dh + 2\pi r h dr

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)

That give us

V= 28 \pi  \, cm^3

Or in decimal value

\boxed{dV= 87.96 \, cm^3}

Thus the volume of metal in the can is 87.96 cubic cm.

6 0
4 years ago
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