The answer is a,(what is the velocity of the current
The forces on one of the wires will be 0.000264 N.It is the field sensed around a moving electric charge that gives rise to the magnetic force.
<h3>What is a magnetic field?</h3>
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The given data in the problem is;
I is the current = 6.50 A
B is the magnetic field=f 2.71 X 10⁻⁵ T
The force on the wire is;
Hence, the force on one of the wires will be 0.000264 N.
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Answer:
Pressure = 20 MPa
Explanation:
Given:
Force acting on the shoe is,
Area of shoe on which the force acts is,
Now, first we convert the area into its standard unit of m².
We have the conversion factor as:
1 cm² =
Therefore, the area of shoe in square meters is given as:
Now, pressure on the shoe is given as:
Plug in 100 N for 'F', for 'A' and solve for 'P'. This gives,
Now, we know that,
Therefore, the pressure acting on the shoe is 20 MPa.
Answer: The gravitational force Fg exerted on the orbit by the planet is Fg = G 4/3πr3rhom/ (R1 + d+ R2)^2
Explanation:
Gravitational Force Fg = GMm/r2----1
Where G is gravitational constant
M Mass of the planet, m mass of the orbit and r is the distance between the masses.
Since the circular orbit move around the planet, it means they do not touch each other.
The distance between two points on the circumference of the two massesb is given by d, while the distance from the radius of each mass to the circumferences are R1 and R2 from the question.
Total distance r= (R1 + d + R2)^2---2
Recall, density rho =
Mass M/Volume V
Hence, mass of planet = rho × V
But volume of a sphere is 4/3πr3
Therefore,
Mass M of planet = rho × 4/3πr3
=4/3πr3rho in kg
From equation 1 and 2
Fg = G 4/3πr3rhom/ (R1 + d+ R2)^2
Answer:
(a):
(b):
Explanation:
<u>Given:</u>
- Charge on one sphere,
- Charge on second sphere,
- Separation between the spheres,
Part (a):
According to Coulomb's law, the magnitude of the electrostatic force of interaction between two static point charges is given by
where,
k is called the Coulomb's constant, whose value is
From Newton's third law of motion, both the spheres experience same force.
Therefore, the magnitude of the force that each sphere experiences is given by
The negative sign shows that the force is attractive in nature.
Part (b):
The spheres are identical in size. When the spheres are brought in contact with each other then the charge on both the spheres redistributes in such a way that the net charge on both the spheres distributed equally on both.
Total charge on both the spheres,
The new charges on both the spheres are equal and given by
The magnitude of the force that each sphere now experiences is given by