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8090 [49]
3 years ago
9

A 350-kg sailboat has an acceleration of 0.62 m/s2 at a angle of 64 degrees north of east find the magnitude and direction of th

e net force that acts on the sail boat
Physics
1 answer:
Kay [80]3 years ago
4 0

Answer:

<em>The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.</em>

Explanation:

<u>Mechanical Force</u>

The second Newton's law states the net force exerted by an external agent on an object of mass m is:

\vec F = m.\vec a

Where \vec a is the acceleration of the object. Note both the force and the acceleration are vectors. The relationship between them is the mass, a scalar.

This means the net force and the acceleration have the same direction.

The sailboat has a mass m= 350 Kg and moves at a=0.62 m/s^2. The magnitude of the net force acting on the boat is:

F=0.62 * 350=217\ N

As stated above its direction is the same as the acceleration, thus:

The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.

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An open organ pipe of length 0.47328 m and another pipe closed at one end of length 0.702821 m are sounded together. What beat f
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Answer:

fb = 240.35 Hz

Explanation:

In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.

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You replace in the equation (1):

f=\frac{343m/s}{2(0.47228m)}=362.36Hz      

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