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8090 [49]
3 years ago
9

A 350-kg sailboat has an acceleration of 0.62 m/s2 at a angle of 64 degrees north of east find the magnitude and direction of th

e net force that acts on the sail boat
Physics
1 answer:
Kay [80]3 years ago
4 0

Answer:

<em>The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.</em>

Explanation:

<u>Mechanical Force</u>

The second Newton's law states the net force exerted by an external agent on an object of mass m is:

\vec F = m.\vec a

Where \vec a is the acceleration of the object. Note both the force and the acceleration are vectors. The relationship between them is the mass, a scalar.

This means the net force and the acceleration have the same direction.

The sailboat has a mass m= 350 Kg and moves at a=0.62 m/s^2. The magnitude of the net force acting on the boat is:

F=0.62 * 350=217\ N

As stated above its direction is the same as the acceleration, thus:

The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.

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W_apparent = 93.1 kg

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we substitute

            W_apparent = ρ_al V g - ρ_fluide g V

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           W_apparent = 93100 g

            W_apparent = 93.1 kg

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<h3>Compare and contrast the energy transfer of a roller coaster to that of a pendulum:</h3><h3>What is the transfer of energy in a roller coaster?</h3>

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<h3>What is the energy transfer in a pendulum?</h3>

As a pendulum swings, its potential energy changes to kinetic energy and kinetic energy changes into potential energy. At the top more potential energy is present.

So we can conclude that When the pendulum and roller coaster move to the top, its has more potential energy whereas when comes to the bottom has more kinetic energy.

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