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3 years ago

Function g is transformed to obtain function h as shown.

Mathematics

2 answers:

stepladder [879]3 years ago

6 0

Answer: A for plato users

Debora [2.8K]3 years ago

5 0

Answer:

Step-by-step explanation:

The transformation is $h(x)=4*g(x+5)$ .

4*g(x+5) means g(x) is vertically shifted by a factor if 4 by multiplying the entire function by 4. The values increase and are stretched (not shrunk to smaller).
g(x+5) means the input x is increased by 5 each time. This results in a horizontal shift left on the graph

The answer is A. The graph of h is the graph of g vertically stretched by a factor of 4 and shifted 5 units to the left.

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Solve pls brainliest

PtichkaEL [24]

Answer:

1 = A 3 = b 4 = c

Step-by-step explanation:

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2 years ago

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

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2 years ago

What expression is equivalent to b+b+b+b

Brums [2.3K]

4b is equivalent to b+b+b+b

5 0

3 years ago

Read 2 more answers

Which equation represents a line parallel to 3x-8y=12?

TEA [102]

Answer:

B. y = -3/8x - 4

Step-by-step explanation:

Given equation: 3x - 8y = 12

Find a parallel line that matches one of the equations shown.

First, find the slope by solving for y:

3x - 8y = 12

8y = -3x + 12

y = -3/8x + 12/8

y = -3/8x + 3/2

Slope m = -3/8

Since the slope of a line parallel is the same slope, the only equation that fits the conditions is B because in the form y = mx + b, m = -3/8

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3 years ago

QUESTION 3<br>3.1 Round the following number up to the nearest whole number<br>R13492.39

ivolga24 [154]

Answer:

the answer is R13492

Step-by-step explanation:

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2 years ago