<span>2.8 x 10^6 N
We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that:
F * 35m = 9.8 x 10^7 kg*m^2/s^2
Solving for F, gives
F * 35m = 9.8 x 10^7 kg*m^2/s^2
F = 9.8 x 10^7 kg*m^2/s^2 / 35m
F = 2.8 x 10^6 kg*m/s^2
F = 2.8 x 10^6 N
So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
Answer: It depends on the terms.
Step-by-step explanation: In fraction terms 16 is equivalent to 4. In number terms 16 is a number larger than 4.
The minimum is 91. The first quartile is 112. The median is 173. The third quartile is 215. The maximum is 253.
Answer:
11%
Step-by-step explanation:
The percentage of the discount is 1012/9200 x 100 = 11%
The lateral area of a cylinder is given by:
Area=πrl+2πr^2
radius,r=12 mm
length,l=5*12=60mm
therefore the lateral area will be:
Area=π*12*60
Area=2,261.95 mm^2
The area of the bases will be:
A=2*π*12^2=904.78 mm^s
The lateral area will be:
2,261.95+904.78
=3,166.73
=3167 mm^2
