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Pavel [41]
2 years ago
9

A principal of  $3300  is invested at  6.75%  interest, compounded annually. How much will the investment be worth after  8  yea

rs? Use the calculator provided and round your answer to the nearest dollar.​
Mathematics
1 answer:
Vitek1552 [10]2 years ago
7 0

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3300\\ r=rate\to 6.75\%\to \frac{6.75}{100}\dotfill &0.0675\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &8 \end{cases} \\\\\\ A=3300\left(1+\frac{0.0675}{1}\right)^{1\cdot 8}\implies A=3300(1.0675)^8\implies A\approx 5565

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How many grams of NH3 are required to produce 4.65 g of HF
nignag [31]

1.326 grams of NH3 are required to produce 4.65 g of HF.

Step-by-step explanation:

Balanced chemical reaction is written first to know the number of moles taking part in original reaction.

NH3 +3 F2 ⇒3 HF  +  NF3

Given:

mass of HF = 4.65

First the number of moles of HF in 4.65 grams is calculated by using the formula:

number of moles (n) = \frac{mass}{atomic mass of 1 mole}

atomic mass of HF = 20 grams/mole

putting the values in the above equation number of moles can be found.

n = \frac{4.65}{20}

  = 0.235 moles of HF are given.

From the equation it can be said that:

1 mole of NH3 reacts to form 3 moles of HF

so, x moles of NH3 would react to form 0.235 moles of HF

\frac{3}{1} = \frac{0.235}{x}

3x = 0.235

x = \frac{0.235}{3}

x = 0.078 moles of NH3 is required.

The moles are converted to mass by applying the formula:

mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)

        putting the values in the formula

mass = 17 X 0.078

mass = 1.326 grams

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