All categories

3 years ago

The function h(x)=x^2+3 and g(x)=x^2-6. If g(x)=h(x)+k, what is the value of k?

Mathematics

1 answer:

Anna [14]3 years ago

3 0

Answer:

-9

Step-by-step explanation:

g(x) - h(x) = k.

Here,

x^2 - 6 - (x^2 + 3) = -6 - 3 = -9

The value of k here is -9.

You might be interested in

If θ is an angle in standard position and its terminal side passes through the point (4,3), find the exact value of \sin\thetasi

vivado [14]

Answer:

0.6

I hope this helps you

:)

3 0

3 years ago

Solve: 3(2d - 1) – 2d = 4(d– 2) + 5

FrozenT [24]

The right answer is No solution.

Look at the attached picture

Hope it will help you

6 0

3 years ago

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent

Ipatiy [6.2K]

Answer:

y = 16.3216X - 330.3904

322 pounds;

Result is significant

Step-by-step explanation:

Given the data:

Chest size, x : 41,54,44,55,39,51

Weight, Y : 328,528,418,580,296,503

Using technology, the prediction model obtained by fitting the data is :

y = 16.3216X - 330.3904

Where, x = chest size ; y = weight

The best predicted weight of a bear with chest size of 40 is

Put x = 40 in the equation :

y = 16.3216(40) - 330.3904

Y = 322.4736

Y = 322 pounds

At α = 0.05

The regression Coefficient, R value obtained is 0.986 ; using this to obtain the Pvalue ;

df = n - 1

Pvalue(0.986, 5) = 0.00198

Since, Pvalue < α ; result is significant at α = 0.05

8 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

What percent of 5 is 3

9966 [12]

Answer:

60% of 5 is 3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers