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MrRissso [65]
3 years ago
9

The data show the chest size and weight of several bears. Find the regression​ equation, letting chest size be the independent​

(x) variable. Then find the best predicted weight of a bear with a chest size of 40 inches. Is the result close to the actual weight of 372 ​pounds? Use a significance level of 0.05.
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

y = 16.3216X - 330.3904

322 pounds;

Result is significant

Step-by-step explanation:

Given the data:

Chest size, x : 41,54,44,55,39,51

Weight, Y : 328,528,418,580,296,503

Using technology, the prediction model obtained by fitting the data is :

y = 16.3216X - 330.3904

Where, x = chest size ; y = weight

The best predicted weight of a bear with chest size of 40 is

Put x = 40 in the equation :

y = 16.3216(40) - 330.3904

Y = 322.4736

Y = 322 pounds

At α = 0.05

The regression Coefficient, R value obtained is 0.986 ; using this to obtain the Pvalue ;

df = n - 1

Pvalue(0.986, 5) = 0.00198

Since, Pvalue < α ; result is significant at α = 0.05

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