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Molodets [167]
3 years ago
10

Evaluate the expression for the given value of the variable. | − 4 b − 8 | + ∣ ∣ − 1 − b 2 ∣ ∣ + 2 b 3 ; b = − 2

Mathematics
2 answers:
Nastasia [14]3 years ago
6 0

Answer:

-11

Step-by-step explanation:

The given expression is:

|-4b-8|+|-1-b^2|+2b^3

=|-(4b+8)|+|-(1+b^2)|+2b^3

=4b+8+1+b^2+2b^3

=4b+9+b^2+2b^3

Substituting the value of b=-2 in above expression, we get

=4(-2)+9+(-2)^2+2(-2)^3

=-8+9+4-16

=-11

Thus, the value of the given expression is -11.

madam [21]3 years ago
5 0

Answer:

The value of expression at b= -2 is -11

Step-by-step explanation:

Given: Expression = \left |-4b-8\right |+\left | -1-b^2\right |+2b^3

To find: Value of given expression when b = -2

Expression

\left |-4b-8\right |+\left | -1-b^2\right |+2b^3

Put, b = -2 in above expression. we get

⇒\left |-4\times(-2)-8\right |+\left | -1-(-2)^2\right |+2(-2)^3

⇒\left |8-8\right |+\left | -1-4\right |+2\times(-8)

⇒\left |0\right |+\left | -5\right |+(-16)

⇒0+5-16

⇒ -11              

Therefore, The value of expression at b= -2 is -11

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Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and
Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates (x_A,y_A)

Vectors AB and AB' are perpendicular, then

\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0

Vectors AC and AC' are perpendicular, then

\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0

Now, solve the system of two equations:

\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.

Subtract these two equations:

5x_A-y_A-8=0\Rightarrow y_A=5x_A-8

Substitute it into the first equation:

x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2

Then

y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0
3 years ago
timomthy began his math homework at 5:17 pm he finished at 5:49 how many minutes did he send on his math homework
daser333 [38]

Answer:

32 minutes

Step-by-step explanation:

49 - 17 = 32

Timothy spent 32 minutes on his math homework.

3 0
3 years ago
Read 2 more answers
6. Use synthetic substitution to evaluate the polynomial P(x) = x - 4x² + 4x – 5 for x = 4
Tatiana [17]

Answer:

When x=4

P(x) =4 - 4(4)^2 + 4(4) -5

=4 - 4(16) + 16 -5

=4 - 64 +11

= -60 + 11

= -49

8 0
3 years ago
Help!!!!!!! solve the inequality
taurus [48]

Answer:

25≥ w

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Step-by-step explanation:

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4 0
4 years ago
How do you solve this problem, ive been working for hours and just cant seem to get it. Help is very much aprrecieated.
zvonat [6]

Answer:

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Step-by-step explanation:

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7 0
4 years ago
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