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stepan [7]
3 years ago
14

Ten times a number is fifty

Mathematics
2 answers:
Rashid [163]3 years ago
7 0

Answer:

5

Step-by-step explanation:

if you multiply 10 and 5, you will get 50

stealth61 [152]3 years ago
3 0
10x5=50 I hope this helped
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Solve this system of equations: X=? Y=? ( JUST WRITE THE NUMBER ANSWERS WITH A COMMA BETWEEN THEM)
hjlf

Answer:

Therefore the Final Solution is

x = 2 and y = 4

( 2 , 4 )

Step-by-step explanation:

Given:

y=2x                ...............Equation ( 1 )

x=-y+6         ................Equation ( 2 )

To Find:

x = ?

y = ?

Solution:

Substitute Equation  ( 1 ) in Equation ( 2 ) we get

x=-2x+6\\\\3x=6\\\\3x=6\\\\x=\frac{6}{3} \\\\\therefore x =2

Now Substituting x = 2 in Equation ( 1 ) we get

y =2\times 2\\\\\therefore y=4

Therefore the Final Solution is

x = 2 and y = 4

( 2 , 4 )

4 0
4 years ago
What num com between 4 and 6?
damaskus [11]

Answer:

5

Step-by-step explanation:

1,2,3,4,5,6

7 0
3 years ago
Read 2 more answers
The table below shows four systems of equations:
Ede4ka [16]
To determine which system of equations would have the same solution, we evaluate each system of equations.

System 1 4x − 5y = 2, 3x − y = 8
x = 38/11
y = 26/11

<span>System 2 4x − 5y = 2, 3x − 2y = 1
x = 1/7
y = -2/7

System 3 4x − 5y = 2, 3x − 8y = 4
x = -4/17
y = -10/17

System 4 4x − 5y = 2, 10x − 9y = 4
x = 1/7
y = -2/7

</span><span>
Therefore, the correct answer is option 3. </span><span>System 2 and system 4 are equal, because the second equation in system 4 is obtained by adding the first equation in system 2 to two times the second equation in system 2.

     4x− 5y = 2 2( 3x − 2y = 1)
-----------------------    10x - 9y = 4</span>
4 0
3 years ago
Bridget works part time in a shoe store. Sometimes when it is not busy, she rearranges the shoes for fun. If she takes six diffe
IRINA_888 [86]
Hi i have an idea  make a pattern to organize the shoes
5 0
3 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
Read 2 more answers
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