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Ivan
3 years ago
5

-1 3/5 ÷-2/3 as a mixed number​

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
6 0

\text{Hey there!}

-1\frac{3}{5}\div\frac{2}{3}

-1\frac{3}{5}=-\frac{8}{5}

\text{Problem becomes:}-\frac{8}{2}\div\frac{2}{3}

\text{Solve that, and you will get:}\frac{-4}{5}\div{\frac{3}{1}}

-4\times1=-4

5\times3=15

\rightarrow =\frac{-4}{15}

\boxed{\boxed{\boxed{\bf{Answer:\frac{-4}{15}}}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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Answer:

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Step-by-step explanation:

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Calling Genius Mathematicians!!!!!! Please Help!!!!!!! 7 and 8!!!!!!
Temka [501]
7) We are given G=Ae^{0.6t}. Recall that e is a real, albeit irrational, number, and it is given that G is the final number of bacteria, A is the initial, t is the time.

We want to solve for t when G = 700 and A = 4.

We substitute into the equation and get 700=4e^{0.6t}, which is \dfrac{700}{4}=e^{0.6t}.

To solve for t, we need to remember that the natural logarithm is the inverse of an exponent with base e. We take the ln of both sides like so.

ln( \frac{700}{4})=ln(e^{0.6t})\\\\ln( \frac{700}{4})=0.6t\\\\t= \frac{5}{3} ln( \frac{700}{4}) = 8.608 \ hours

8) We are solving the equation for t when P = 5,000, r = 2% = 0.02, n = 12 (it's compounded 12 times in a year), and A = 10,000. 

10000=5000(1+ \dfrac{0.02}{12})^{12t}

We first divide both sides by 5,000. Then, we take the natural log (ln) of both sides and simplify to solve for t.

t = 34.686 years



8 0
3 years ago
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