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liq [111]
3 years ago
10

Find the product.

Mathematics
2 answers:
s2008m [1.1K]3 years ago
6 0

Answer:

The answer is C i got it correct in edmentum

Step-by-step explanation:

prohojiy [21]3 years ago
3 0

Answer:

A. -14 B.-57 C.-14 D.-25

(I USED MY BRAIN SO IT MIGHT BE WRONG)

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If David plays 3 tennis matches every week for 9 weeks, how many matches will he play altogether
kari74 [83]
If he plays 3 matches a week for 9 weeks, you have to multiply 3&9.
3*9=27
Daniel will have played 27 tennis matches by the end of the 9 weeks.
Hope this helps:)
5 0
3 years ago
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I need help please ..
koban [17]

A is 18

B is 162

C is 18

D is 162

4 0
3 years ago
What are trapezoids?
postnew [5]

Answer:

Is a quadrilateral with one pair of opposite sides parallel

Step-by-step explanation:

7 0
2 years ago
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In a new york state daily lottery game, a sequence of four digits (not necessarily different) in the range 0-9 are selected at r
Anna [14]
<span>There are 10,000 (10*10*10*10) possible sequences. There are 4C3 ways, 4, of having exactly three digits be the same value. The differing digit can be any of the four positions. There are 10P2 ways, 90 (10*9), to choose the digits of the sequence since we have 10 choices for the digit to be repeated, then 9 more options or the differing digit. The product of the combination arrangements and permutation selection, 4*90, shows there are 360 sequences with three of the same digit. Thus the probability is 360/10,000 or 0.036 or 3.6%.</span>
8 0
3 years ago
Find the equation of the line that is perpendicular to the line y = (-1/3)x -1 and passes through the point (1, 5)?
Anit [1.1K]

bearing in mind that perpendicular lines have negative reciprocal slopes, so


\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{1}\implies 3}}


so we're really looking for a line whose slope is 3 and runs through (1,5)


\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3(x-1) \\\\\\ y-5=3x-3\implies y=3x+2

4 0
3 years ago
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