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2 years ago

12

An employee working at an electronic store earned $3582 for working 3 months during the summer what did the employee earn the fi

rst 2 months

1 answer:

Sophie [7]2 years ago

5 0

Answer - 2388$
3582 x
-------- = ------
3 2

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(: IF U HELP ME U WILL GET POINTS, A STAR AND A THANK YOU AND U WILL ALSO GET BRAINLIST! (MATH) :)

kumpel [21]

Answer:

Step-by-step explanation:

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2 years ago

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A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude o

Semenov [28]

Answer:

A

Step-by-step explanation:

A is correct because if the minimum is 29,000 feet, x (the airplane altitutude) must be greater than or equal to 29,000 ft. Since the maximum is 41,000 feet, x must be less than or equal to that number.

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2 years ago

Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?

Anit [1.1K]

Answer:

$\dfrac{p^{7} q}{160}$

Step-by-step explanation:

$\dfrac{(4p^-4 q)^-2}{10pq^-3} =$

$= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}$

$= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}$

$= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}$

$= \dfrac{1}{160}p^{7} q$

$= \dfrac{p^{7} q}{160}$

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2 years ago

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Help me please I’m begging you:(

alex41 [277]

Answer:

Chips = 14

Pretzel = 14

Cookie = 8

Popcorn = 13

Question Mark = 222

Step-by-step explanation:

First Equation:

Chips + Pretzel + Chips = 42

Third Equation: Chips = Pretzel.

This means that

Pretzel + Pretzel + Pretzel = 42

Pretzel = $\frac{42}{3} =14$

Chips = Pretzel

Chips = $14$

Second Equation:

Cookie + Chips + Cookie = 30

We know that Chips = 14.

Cookie + 14 + Cookie = 30

Subtract 14 on both sides:

Cookie + Cookie = 16

Cookie = $16\div 2 =8$ .

Fourth Equation:

Cookie + Cookie + Popcorn = 29

We know that Cookie = 8.

8 + 8 + Popcorn = 29

16 + Popcorn = 29

Subtract 16 on both sides:

Popcorn = 13.

Question Mark:

(Popcorn + Popcorn) $\times$ Cookie + Chips = (13 + 13) $\times$ 8 + 14 = 26 $\times$ 8 + 14 = $208+14=222$

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2 years ago

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A standardized exam's scores are normally distributed. In a recent year, the mean test score was 14901490 and the standard dev

kicyunya [14]

<h2>Answer with explanation:</h2>

Given : A standardized exam's scores are normally distributed.

Mean test score : $\mu=1490$

Standard deviation : $\sigma=320$

Let x be the random variable that represents the scores of students .

z-score : $z=\dfrac{x-\mu}{\sigma}$

We know that generally , z-scores lower than -1.96 or higher than 1.96 are considered unusual .

For x= 1900

$z=\dfrac{1900-1490}{320}\approx1.28$

Since it lies between -1.96 and 1.96 , thus it is not unusual.

For x= 1240

$z=\dfrac{1240-1490}{320}\approx-0.78$

Since it lies between -1.96 and 1.96 , thus it is not unusual.

For x= 2190

$z=\dfrac{2190-1490}{320}\approx2.19$

Since it is greater than 1.96 , thus it is unusual.

For x= 1240

$z=\dfrac{1370-1490}{320}\approx-0.38$

Since it lies between -1.96 and 1.96 , thus it is not unusual.

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2 years ago